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Difficulty in understanding the trigonometry in applying the momentum equation for a stream tube

You differential element is At an angle $\theta \ $with respect to x axis but the weight vector is pointing down. . You can think of $F_g.sin \theta$ as the inclined component of the weight of the ...
kamran's user avatar
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Difficulty in understanding the trigonometry in applying the momentum equation for a stream tube

Since $\sin(\theta)\in [-1, 1]$, that would mean $\left|F_g/\sin(\theta)\right|\ge F_g$. So $F_g$ would produce greater force than itself in the $s$ direction and as the angle $\theta$ approaches 0, ...
Tomáš Létal's user avatar

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