# Tag Info

0

No, there is a problem with the question. If the flow rate is set at the inlet, then that is the flow through the pipe, period. The pump doesn't add mass, just a motive force. Bernouli would apply if you were doing the flow calcs yourself. In this case, they gave you the answer at the beginning. The flow rate through the exit will be equal to the flow ...

1

Solar Mike is correct, but requires more explanation why. The Bernoulli equation is an energy conservation law. The pump is imparting energy on the fluid, therefore, needs to be accounted for as a pressure addition term. When you applied continuity initially, you are assuming the flow is incompressible (correct assumption) with no energy addition between the ...

1

There are a lot of ways. To cut cost, reduce your expensive sensors to a bare minimum - probably just measuring what goes into the reactor. Controlling by mass tends to be expensive compared to by volume or pressure. Ideal gas law is your friend here. Pressure times volume is proportional to number of particles times temperature. It's pretty inexpensive ...

0

Tank level too low to prime Pump1. Pump2 primes Pump1. So far OK. Pump1 turns on, and both for recirculation and taking some load off Pump2. Probably OK thanks to recirculation making up flow difference. Pump2 turns off. This is where things get a little hairy since Pump1 might actually end up driving Pump2 and Pump2 may not handle that. solution is a ...

0

The two critical variables for flow rate will be resistance and diameter/area of flow. The holes in the outer zones could be over drilled to increase their diameters. If that is not an option then reducing the number of holes in the central zone and increasing the number of holes in the out zone would help. Alternatively, as others have stated, you could ...

0

you could add a diverter fin like a n inverse V inside to give favore to the side openins and deny direct suction from center openings. as per my sketch.

1

I would suggest separate channels to each set of holes with orifice plates to limit the flow to / from each. That way you can control each set individually. The other solution will be to over-specify the flow rate so that the poorest one is sufficient...

1

It will be a next to impossible task to try and analytically predict the number/position/size of the holes in order to have exactly the same flow. Even if you do for a temperature and a set humidity, at different temperatures you might have unacceptable results. If you are really interested in equalising the flows, a better alternative is to use a flow ...

0

If you are really going to just change the pressure, with essentially no moving parts, the simplest way to do this is just by using diffusers. In a fluid flow there is 3 types of pressure: 1) dynamic head, 2) static head, and 3) elevation head. Static head refers to the pressure of a fluid when it is at rest a.k.a. not moving. The value depends on the ...

1

What you are seeing in the video is a vacuum generator/vacuum ejector/aspirator. Figure 1: Venturi effect (source: wikipedia) It uses the principle of the Venturi effect. I.e. that for steady, incompressible, inviscid when there is an increase of speed there is a drop in static pressure. This is mathematically expressed as: p_1-p_2 =\frac{\rho}{2} (v_2^2- ...

Top 50 recent answers are included