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My interpretation is "the force causing the rod to pressure the hydraulic cylinder that results in 640 N compressive force in the rod/cylinder, and a net moment/torque of 30 Nm about the pivot point. If so, the force should be: $0.2F + 30 - 640*0.13 = 0$ $F = 266 N$ Other than the 30 Nm moment, the pivot point has a horizontal force that is equal to $...


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Unless there are other clarifying statements on the text not being shown here, you are right. There is one extra piece of date here that crashes the equation. They have already supplied the wrong answer. The question is wrong. If you start from the moment on the pedal you absolutely get 150 N force at the piston. And if you accept640N force at the piston you ...


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The first one is the correct, because you are given the distance (perpendicular to F). On the second one, you don't know the direction of the force compared to the rod .


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