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First off we assume you meant parallel flow because there is no flow perpendicular to a wall, there may be pressure, static and dynamic. Depending on the current velocity, type of flow, flexibility of the plate, the case will start looking like an open channel flow. If the plate is too flexible it could deform into convex and concave undulations giving rise ...


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The key principle is that, when expressed in terms of the non-dimensional head coefficient $K_H := gH/\left(D\omega\right)^2$ and the non-dimensional flow coefficient $K_Q := Q/\left(D^3\omega\right)$, there is a single head-flow characteristic for the whole family of geometrically similar pumps. That is to say, when expressed in terms of those quantities, ...


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We know $Q = AV$, and $A = \pi$$D^2/4$, let's rearrange the terms and get to the root "D": $Q_1^2 = (A_1V_1)^2 = (\pi$$D_1^2V_1/4)^2$ = $(70-H_1)/1.41 * 10^{-3}$ $D_1^2 = (4/V_1\pi)\sqrt{(70 - H_1)/1.41 * 10^{-3})}$ $D_1 = \sqrt{(4/V_1\pi)\sqrt{(70 - H_1)/1.41 * 10^{-3})}} $ You can do the same for $D_2$ and get $D_1/D_2$. (First to check my ...


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