You are mis-reading the tables or trying to get a value you cannot get via temperature and pressure. Your question didn't make sense to me, so I consulted my dad's Thermodynamics text book just top make sure (Emswiler & Schwartz, McGraw-Hill, 1943, $3.50 USD, used by him for his BSME degree, class of 45). This book is fine for our use because nothing ...
Specific heat capacity of steel is 0.466. In other words it takes 0.466 joules to raise the temperature of one gram of steel one degree Celsius. So how hot is the steel initially. In your case 90 degrees to get down to 30 you must remove from 90,000 grams, or 2.5 megajoules.
Forced air cooling for example of electronics electronic components use fan cooling. ...
Calculate the heat to be extracted from the steel. You'll need to look up the SHC of steel.
Calculate what mass of 30°C air will be required to absorb that much heat.
Calculate the volume of that mass of air. That answers the question in your question title.
Flow rate is volume / time.
We define reactions uniquely depending on the reactants and products. Here are examples related to your question.
Formation: Na(s) + (1/2)Cl$_2$(g) $\rightarrow$ NaCl(s)
Lattice Formation: Na$^+$(g) + Cl$^-$(g) $\rightarrow$ NaCl(s)
Solution: NaCl(s) $\rightarrow$ NaCl(aq)
Hydration: Na$^+$(g) $\rightarrow$ Na$^+$(aq)
Atomization: Na(s) $\rightarrow$ Na(g)