Suppose a closed sphere with a hull and an $R$-value of $10$ m2 K/W and a radius of $1$ m. Suppose the temperature inside of the sphere is Ti, the temperature outside is To. The inside temperature is kept at Ti with a heat pump.
A common way to measure R-value is to assume $T_i \gg T_0$. The thin layer of air causes a slightly different temperature at the inside surface of the sphere, $T_f$. The $R$-value of such air layer is known and hence: $R_{air} \ / \ (T_i-T_f) = R \ / \ (T_f-T_0)$ and can be solved for $R$. But this requires $T_i >> T_0$.
Now, suppose in $I$ plot $T$ versus $t$ (time). When the heat pump turns off, the sphere will be slowly getting colder as heat moves out. If I wait long enough $T_i = T_0$. The speed at which this occurs should depend on the $R$ value (and surface area).
So, I am wondering, given $T(t)$ and/or $∆T /∆ t$, can I estimate the sphere's $R$-value? If yes, how? If not, why not?