0
$\begingroup$

I'm studying this text about buckling.

There a factor called $\lambda_1$ is defined:

$$\lambda_1=\pi \sqrt{\frac{E}{f_y}}=93.9\sqrt{\frac{235}{f_y}}$$

But how was that last step made? Where did that factor of 93.9 come from? Usually we take the elastic modulus of structural steel as around 200GPa, so how is there 235 under the square root? I feel like there is some step missing.

$\endgroup$
2
  • $\begingroup$ What assumptions are stated in the text? I'm not chasing the text to do the reading though. $\endgroup$
    – Solar Mike
    Commented Dec 15, 2020 at 12:58
  • $\begingroup$ 93.9 was declared as the legal value of pi in the state of Indiana :) $\endgroup$ Commented Dec 15, 2020 at 21:36

1 Answer 1

1
$\begingroup$

Edit

I have changed the units to MPa, basically cranking their numbers back to see what unit they have used for E.

Without looking at your source, it makes sense if they are using the unit of MPa.

$E=210.000MPa$

then:

$$\lambda_1=\pi\sqrt\frac{210,000}{F_y}=\sqrt\frac{893.617*235}{F_y}$$

$\lambda_1=93.91\sqrt\frac{235}{F_y}$

$\endgroup$
7
  • $\begingroup$ For steel E = 210GPa, not 210kPa. 210kPa is 1000 times more "floppy" than polystyrene foam. $\endgroup$
    – alephzero
    Commented Dec 15, 2020 at 16:36
  • $\begingroup$ @alephzero, Thanks it was a typo, I fixed it. I used the correct value in my calcs tho. and the answer is correct. $\endgroup$
    – kamran
    Commented Dec 15, 2020 at 17:06
  • $\begingroup$ The unit is still wrong. There is also an error in the calculations. But the principle is correct. $\endgroup$
    – ingenørd
    Commented Dec 15, 2020 at 19:52
  • $\begingroup$ sorry, I am babysitting my grand daughter. I fix the arithmetic later. $\endgroup$
    – kamran
    Commented Dec 15, 2020 at 20:15
  • $\begingroup$ I'm sorry but I think your math is still wrong. How do you get 93.91 as the square root of 893617? I get approximately 945.31.. $\endgroup$
    – S. Rotos
    Commented Dec 17, 2020 at 12:40

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Not the answer you're looking for? Browse other questions tagged or ask your own question.