3
$\begingroup$

I am having trouble conceptualizing this problem. I have attempted it but am confused about a few things, I would highly appreciate any insight or advice for this.

image question

I know you need to resolve P into its Y and Z components and that you can move them to the end of the beam.

I understand Py causes bending in the XZ plane and Pz causes bending in the YX plane.

I thought that Pz contributed to σzz and Py contributed to σyy.

But, my lecturer said that both Py and Pz contribute to σxx.

I'm a little confused as to how this is possible when they are orthogonal to each other.

Both cause bending on the beam (Py causes torsion) but do they not bend the beam in different planes therefore shouldn't they contribute to different stresses?

$\endgroup$
1
  • $\begingroup$ you should resolve the load as a force (magnitude P and torque 2 P Cos(30) ), then work the shaft problem in a coordinate system aligned with the vector load direction. $\endgroup$
    – agentp
    Commented Mar 15, 2018 at 14:21

1 Answer 1

2
$\begingroup$

The confusion seems to arise from a misconception about how $\sigma$ is defined. For example, $\sigma_{yy}$ corresponds to a force in the $y$ direction applied to a surface facing the $y$ direction. Both $\sigma_{yy}$ and $\sigma_{zz}$ are zero essentially everywhere in the shaft (idealizing it as long and narrow) because there's no distributed region where a $y$-or $z$-direction force is internally or externally applied to a $y$- or $z$-direction surface, respectively.

(I'm not including the point loads at either end, which are localized. It's implicit in these problems that stress concentrations can be ignored and that failure doesn't arise directly in the attachment, though it may occur within the shaft adjacent to the attachment or point of load application.)

Instead, $\sigma_{xx}$ and $\tau$ are the key parameters (and the only nonzero stress components in this idealized problem), and the first varies strongly with the location on the shaft. For example, the $y$-direction component of $P$ causes a location-dependent tensile stress $\sigma_{xx}$ (i.e., locations with positive $\sigma_{xx}$) on the top of the shaft as a result of the bending moment). The $z$-direction component causes a location-dependent compressive stress $\sigma_{xx}$ on the left side of the shaft, also arising from the bending moment. The torque causes a shear $\tau$ that's maximized on the surface of the shaft.

The key point is that a single stress component is not necessarily uniform in an object; here, for example, $\sigma_{xx}$ varies across the surface and interior of the shaft.

This is a very important point, so I suggest reviewing a good mechanics of materials text (e.g., Beer and Johnston) until it's familiar.

$\endgroup$
1
  • $\begingroup$ Thank you so much for your help again, I really appreciate it :) $\endgroup$
    – gunter
    Commented Mar 16, 2018 at 7:20

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Not the answer you're looking for? Browse other questions tagged or ask your own question.