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\begin{array}{cc} & 0x &\ 1 &\ F &\ F &\ F &\ F &\ F &\ F &\ F \\ - &0x &\ 0 &\ 0 &\ 1 &\ 0 &\ 0 &\ 0 &\ 0 &\ 0 \\ + &0x &\ 0 &\ 0 &\ 0 &\ 0 &\ 0 &\ 0 &\ 0 &\ 1 \\ = &0x &\ 1 &\ F &\ F &\ 0 &\ …

You cannot get 2kV from a relay unless you have 2kV available. Transformer. $$Turns\ ratio = \frac {V_{High}} {V_{Low}}$$

Kirchhoff's Voltage Law (KVL) must be satisfied. You are fixiated on: $$ \beta = \frac {I_C}{I_B}$$ So $I_C$ must be larger than $I_B$, but this implies the transistor is operating in the active re …

From the values 198 to 242 ohm. What does this mean? If you measure the resistance of the resistor, it should measure a specific value in this range at room temperature, if it is within tolerance. Th …

You haven't said if your loads are motors or whether your voltages are line or phase. I'll assume voltages are line. $P_T = 20kW$ $$P_T = \sqrt {3}\ V_{Line}\ I_{Line}\ cos \ \theta$$ $$I_{Line} …

H would have to be your switch. You may have to use switch debounce. Use $Q$ or $\bar Q$ as required to get triggering as required. Adjust 1kΩ and 10μF to get LED to function as you want. Little …

You have two problems. First, the obvious, you have not taken the resistance of probes into account. Ohm's Law must be satisfied. Second, TP-60052 TWINTEX is a Dual Channel Power Supply only rated fo …

From ixfn48n50 datasheet: So $R_{DS_{ON}} = 0.10\Omega$, which means KVL (Kirchhoff's Voltage Law) when your Power MOSFET turns on is: $$V_{DD} - V_{DS} - V_{R_G} = 0$$ $$I_{D} = \frac {340V} {0.10\O …

Here is the corrected schematic for the uxcell Digispark Kickstarter Attiny85 Micro USB Development Board. Original schematic. I say corrected because parts of the internet has gotten the direction …

Depends on what is on, the size of the vessel and port accomodations for carbon emissions. Once connected, shore power goes to the main switchboard so anything can be on. But typically lights, outlet …

Ideal transformer - transformation ratio $$\alpha = \frac {V_1} {V_2} = \frac {N_1} {N_2} = \frac {I_2} {I_1}$$ Apparent Power: $$S_1 = S_2$$ Real transformer: $$\alpha = \frac {V_1} {V_2} = \frac {N_ …

Power rating of a motor is the mechanical power out. Divide that by efficiency and you should roughly get electrical power in. Efficiency will be different if not at full-load. To get 6W mechanical …

If you notice, you need 20 bits to access the 1Mb byte modules. But your processor is word aligned. So 2 1Mb byte modules form a 2Mb word module. The key to understanding how it works is the Misa …

Losses are due to skin effect. Direct current flows through the full cross-sectional area (CSA) of the, typically aluminum, conductor, while alternating current flows on the outer surface of the cond …

Your formulas are wrong. $$pf = \frac {P}{S}$$ If you sketch the power triangle, $cos\ \theta = \frac {Adjacent}{Hypotoneuse} = \frac {P}{S}$, which means $pf = cos\ \theta$. Basic right triangles an …