When calculating 0.2% offset from stress strain curve please,

do I take 0.2% of the original length and then, divide this by original length to get strain and plot this please?

And for resilience, is it integration from 0 strain to 0.2% offset strain of the yield stress with respect to strain please?

Thank you


1 Answer 1


Strain is determined as $\epsilon = (l - l_o)/l_o$. The 0.2% offset strain is the point where $\epsilon = 0.002$. The 0.2% offset stress is determined by using a line that has the same slope as the initial stress strain ... the initial Young's modulus. In materials that are fully elastic up to and beyond this point, the initial slope remains constant. In some cases, the stress-strain curve has a curvature to it. Polymers are an example where the modulus changes as a function of strain.

Resilience is the integrated area under the stress-strain curve up to the point of strain that you define. It is technically a term only to be used for elastic behavior. After yield, the integrated area is the toughness.

A plot below shows these concepts graphically.

stress-strain plot with offset and resilience

The area under the curve is $R = \int \sigma\ d\epsilon$. When $\sigma = E \epsilon$ and $E$ is constant, the resilience at any $(\sigma,\epsilon)$ point along the elastic straight line becomes the area under a right triangle $R = E\epsilon^2/2 = \sigma\epsilon/2 = \sigma^2/2E$.

  • $\begingroup$ For resilience please, is it right to then do 1/2(strain)(stress at yield) $\endgroup$ Apr 15, 2021 at 18:45
  • $\begingroup$ I've address the question in the answer. $\endgroup$ Apr 15, 2021 at 19:09
  • $\begingroup$ Thank you Jeffrey, sorry when you get Ee^2/2 wouldn’t that become stress(e)/2 not stress/2(e) please? $\endgroup$ Apr 15, 2021 at 20:42
  • $\begingroup$ Yes. I fixed it. $\endgroup$ Apr 16, 2021 at 0:57

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