I have an old bend/twisted wooden door. It has some character to it so I want to keep it and add square metal bars to straighten it. I have provided a sample drawing of the door and where it is twisted. I have drilled a hole in the upper most open part and if I pull with a scale I am able to straighten it with about 20kg (I haven't used a scale yet, but I will)
I intend to put square metal bars on the bent sides (maybe even inside and out) and straighten the wood.
My question is what is the formula that I can use to calculate the size of the metal bar? For example I see there is a square profile bar 40x40x3mm that I will be able to buy and attach. So, is this going to be enough for the long side 2m and for the short side 1m? I can also order this square profile bar to be slightly bent and attach it so the two bends - the one of the wood and the one of the metal counter each other. But I am not really willing to go that way. I think its way too complicated.
Thank you in advance.
- I think a visible rectangle bar on one or both faces will be stronger and more simple to attach, so I will go with that.
- No bend is acceptable - I want it straight.
- So the next question following the comment is how much of a bend do I need for what type of bar for each of the sides - short(1m) and long (2m)?