How does Force Effect https://forceeffect.autodesk.com do it? Given a 10m long bar angled as the hypotenuse of a 3, 4, 5 triangle with an xy pin constraint a (0,0), another xy constraint at (4,3), and a vertical force of 100N applied down at (10,6) Force Effect calculates the x and y reaction forces below at C and A. I am not as interested in this particular answer in how to get to it by a codeable algorithm.
So the equations are:
Sum Moments about C = 0 => Y$_{ca}$(R$_{ax}$) + X$_{ca}$(R$_{ay}$) + X$_{cb}$(F$_{1}$) = 0 => 3 R$_{ax}$ - 4 R$_{ay}$ = -4(-100)
Sum Moments about A = 0 => Y$_{ac}$(R$_{cx}$) + X$_{ac}$(R$_{cy}$) + X$_{ab}$(F$_{1}$) = 0 => - 3 R$_{cx}$ + 4 R$_{cy}$ = -8(-100)
Sum Forces Y = 0 => R$_{ay}$ + R$_{cy}$ + F$_{1}$ = 0 => R$_{ay}$ + R$_{cy}$ = -(-100)
Sum Forces X = 0 => R$_{ax}$ + R$_{cx}$ = 0
Which could translate to a 4x4 matrix: Ax = b
| 3. -4. 0. 0. | | Rax | = | 400 |
| 0. 0. -3. 4. | | Ray | = | 800 |
| 0. 1. 0. 1. | | Rcx | = | 100 |
| 1. 0. 1. 0. | | Rcy | = | 0 |
And attempting to solve for x = inv(A)* b gives the following error in SciLab (or MatLab) -->inv(A) !--error 19 Problem is singular.
So the matrix is not invertible- whatever that means!
I’d be open to some sort of substitution method to solve it if that is any easier.
This is not homework. This is a simplified version of a real-world problem of a large free body being held in place by two fixed pins. It is not dynamic – nothing is moving.