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If I have an electric vehicle on an incline (m=17,300 kg) I want to figure out how much energy it would generate by regenerative braking.

I've used $a= g \cdot \sin({\theta}) $ and $f=m\cdot a$.

at 05 deg incline, acceleration is 0.85 m/s/s; this creates a force of 11114.972 N
at 10 deg incline, acceleration is 1.70 m/s/s; this creates a force of 22145.352 N

So bearing these values in mind if I don't want to accelerate and maintain a set speed I will need to create a braking force of 1111511114.972 N at 5 deg incline - this in turn will keep the machine at the same speed (ignoring friction, bumpy/uneven surface, etc.).

How can I figure out the Watts generated for the regenerative braking force of 1111511114.972 N?

The DC motor (I think it's 3 phase) is a 105 kW motor rated at 350 V and 300 A, max torque is 190 Nm @ 285 V drawing 285 A. (That's all the information I have for the motor.) Efficiency of the motor would be 0.85 (Assumed).

If I have an electric vehicle on an incline (m=17,300 kg) I want to figure out how much energy it would generate by regenerative braking.

I've used $a= g \cdot \sin({\theta}) $ and $f=m\cdot a$.

at 05 deg incline, acceleration is 0.85 m/s/s; this creates a force of 11114.972 N
at 10 deg incline, acceleration is 1.70 m/s/s; this creates a force of 22145.352 N

So bearing these values in mind if I don't want to accelerate and maintain a set speed I will need to create a braking force of 11115.972 N at 5 deg incline - this in turn will keep the machine at the same speed (ignoring friction, bumpy/uneven surface, etc.).

How can I figure out the Watts generated for the regenerative braking force of 11115.972 N?

The DC motor (I think it's 3 phase) is a 105 kW motor rated at 350 V and 300 A, max torque is 190 Nm @ 285 V drawing 285 A. (That's all the information I have for the motor.) Efficiency of the motor would be 0.85 (Assumed).

If I have an electric vehicle on an incline (m=17,300 kg) I want to figure out how much energy it would generate by regenerative braking.

I've used $a= g \cdot \sin({\theta}) $ and $f=m\cdot a$.

at 05 deg incline, acceleration is 0.85 m/s/s; this creates a force of 11114.972 N
at 10 deg incline, acceleration is 1.70 m/s/s; this creates a force of 22145.352 N

So bearing these values in mind if I don't want to accelerate and maintain a set speed I will need to create a braking force of 11114.972 N at 5 deg incline - this in turn will keep the machine at the same speed (ignoring friction, bumpy/uneven surface, etc.).

How can I figure out the Watts generated for the regenerative braking force of 11114.972 N?

The DC motor (I think it's 3 phase) is a 105 kW motor rated at 350 V and 300 A, max torque is 190 Nm @ 285 V drawing 285 A. (That's all the information I have for the motor.) Efficiency of the motor would be 0.85 (Assumed).

SI units should be separated by a space from their values. Instead of a little bold "Q", draw attention to your question by bolding the whole thing. Copy editing.
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Regenerative How can I determine the power generated by a regenerative braking system?

If I have an electric vehicle on an incline (m=17,300 kg) I want to figure out how much energy it would generate by regenerative braking.

I've used: $ acceleration = g · \sin({\theta}) $$a= g \cdot \sin({\theta}) $ and using $f=m·a$$f=m\cdot a$.

at 05 deg incline, acceleration is 0.85 m/s/s; this creates a force of 11114.972 N
at 10 deg incline, acceleration is 1.70 m/s/s; this creates a force of 22145.352 N

So bearing these values in mind if I don't want to accelerate and maintain a set speed I will need to create a braking force of 11115.972N972 N at 5 deg incline - this in turn will keep the machine at the same speed. (ignoring friction, bumpy/uneven surface, etc.).

Q:How can I figure out the Watts generated for the regenerative braking force of 11115.972 N? What formulas can I use to figure out the Watts generated for the regenerative braking force of 11115.972N?

The DC motor (I think it's 3 phase) is a 105kW105 kW motor rated at 350V350 V and 300A300 A, max torque is 190Nm190 Nm @ 285V285 V drawing 285A285 A. (That's all the information I have for the motor).) Efficiency of the motor would be 0.85 (Assumed).

Regenerative braking

If I have an electric vehicle on an incline (m=17,300 kg) I want to figure out how much energy it would generate by regenerative braking.

I've used: $ acceleration = g · \sin({\theta}) $ and using $f=m·a$

at 05 deg incline, acceleration is 0.85 m/s/s; this creates a force of 11114.972 N
at 10 deg incline, acceleration is 1.70 m/s/s; this creates a force of 22145.352 N

So bearing these values in mind if I don't want to accelerate and maintain a set speed I will need to create a braking force of 11115.972N at 5 deg incline - this in turn will keep the machine at the same speed. (ignoring friction, bumpy/uneven surface etc.).

Q: What formulas can I use to figure out the Watts generated for the regenerative braking force of 11115.972N?

The DC motor (I think it's 3 phase) is a 105kW motor rated at 350V and 300A, max torque is 190Nm @ 285V drawing 285A. (That's all the information I have for the motor). Efficiency of the motor would be 0.85 (Assumed).

How can I determine the power generated by a regenerative braking system?

If I have an electric vehicle on an incline (m=17,300 kg) I want to figure out how much energy it would generate by regenerative braking.

I've used $a= g \cdot \sin({\theta}) $ and $f=m\cdot a$.

at 05 deg incline, acceleration is 0.85 m/s/s; this creates a force of 11114.972 N
at 10 deg incline, acceleration is 1.70 m/s/s; this creates a force of 22145.352 N

So bearing these values in mind if I don't want to accelerate and maintain a set speed I will need to create a braking force of 11115.972 N at 5 deg incline - this in turn will keep the machine at the same speed (ignoring friction, bumpy/uneven surface, etc.).

How can I figure out the Watts generated for the regenerative braking force of 11115.972 N?

The DC motor (I think it's 3 phase) is a 105 kW motor rated at 350 V and 300 A, max torque is 190 Nm @ 285 V drawing 285 A. (That's all the information I have for the motor.) Efficiency of the motor would be 0.85 (Assumed).

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If I have an electric vehicle on an incline (m=17,300 kg) I want to figure out how much energy it would generate by regenerative braking.

I've used: $ acceleration = g · \sin({\theta}) $ and using $f=m·a$

at 05 deg incline, acceleration is 0.85 m/s/s; this creates a force of 11114.972 N
at 10 deg incline, acceleration is 1.70 m/s/s; this creates a force of 22145.352 N

So bearing these values in mind if I don't want to accelerate and maintain a set speed I will need to create a braking force of 11115.972N at 5 deg incline - this in turn will keep the machine at the same speed. (ignoring friction, bumpy/uneven surface etc.).

Q: What formulas can I use to figure out the Watts generated for the regenerative braking force of 11115.972N?

The DC motor (I think it's 3 phase) is a 105kW motor rated at 350V and 300A, max torque is 190Nm @ 285V drawing 285A. (That's all the information I have for the motor). Efficiency of the motor would be 0.85 (Assumed).


My solution:

a=g·sin(Θ) then I used the acceleration to find the force; f=m·a ; Since I know the radius of the tyre/wheel is (0.525m), I can work out the torque: torque=wheelradius·force ; converting a preset speed of 15kph to rad/s of the wheel is 5.29rad/s - I now know the torque and the angular velocity (in rad/s) I can work out power generated = Power = τ·ω = Nm·rad/s.

In one line P=(m·g·sin(Θ)·Wheelradius)·(angular velocity of wheel) for example P=(17300·9.81·sin(45))·(7.94)=500,241.731W or 500.2kW at 45 deg incline at 15 kph.

If I have an electric vehicle on an incline (m=17,300 kg) I want to figure out how much energy it would generate by regenerative braking.

I've used: $ acceleration = g · \sin({\theta}) $ and using $f=m·a$

at 05 deg incline, acceleration is 0.85 m/s/s; this creates a force of 11114.972 N
at 10 deg incline, acceleration is 1.70 m/s/s; this creates a force of 22145.352 N

So bearing these values in mind if I don't want to accelerate and maintain a set speed I will need to create a braking force of 11115.972N at 5 deg incline - this in turn will keep the machine at the same speed. (ignoring friction, bumpy/uneven surface etc.).

Q: What formulas can I use to figure out the Watts generated for the regenerative braking force of 11115.972N?

The DC motor (I think it's 3 phase) is a 105kW motor rated at 350V and 300A, max torque is 190Nm @ 285V drawing 285A. (That's all the information I have for the motor). Efficiency of the motor would be 0.85 (Assumed).


My solution:

a=g·sin(Θ) then I used the acceleration to find the force; f=m·a ; Since I know the radius of the tyre/wheel is (0.525m), I can work out the torque: torque=wheelradius·force ; converting a preset speed of 15kph to rad/s of the wheel is 5.29rad/s - I now know the torque and the angular velocity (in rad/s) I can work out power generated = Power = τ·ω = Nm·rad/s.

In one line P=(m·g·sin(Θ)·Wheelradius)·(angular velocity of wheel) for example P=(17300·9.81·sin(45))·(7.94)=500,241.731W or 500.2kW at 45 deg incline at 15 kph.

If I have an electric vehicle on an incline (m=17,300 kg) I want to figure out how much energy it would generate by regenerative braking.

I've used: $ acceleration = g · \sin({\theta}) $ and using $f=m·a$

at 05 deg incline, acceleration is 0.85 m/s/s; this creates a force of 11114.972 N
at 10 deg incline, acceleration is 1.70 m/s/s; this creates a force of 22145.352 N

So bearing these values in mind if I don't want to accelerate and maintain a set speed I will need to create a braking force of 11115.972N at 5 deg incline - this in turn will keep the machine at the same speed. (ignoring friction, bumpy/uneven surface etc.).

Q: What formulas can I use to figure out the Watts generated for the regenerative braking force of 11115.972N?

The DC motor (I think it's 3 phase) is a 105kW motor rated at 350V and 300A, max torque is 190Nm @ 285V drawing 285A. (That's all the information I have for the motor). Efficiency of the motor would be 0.85 (Assumed).

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