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enter image description here

$s=R\tilde{s}$ is fine, but why $\theta=R\tilde{\theta}$? Namely: why vectors of linearised rotations $\theta_i$ and $\theta_j$ (at nodes $I$ and $j$ respectively) are rotated like they were vector displacements $s_i$ and $s_j$? For instance, rotating a frame in 2D by an angle $\alpha$, the initial rotation $\tilde{\theta}$ of a vector displacement $\tilde{s}$ becomes a final rotation $\theta$ in the new frame such that $\theta=\tilde{\theta}+\alpha$ and not $\theta=R\tilde{\theta}$. I don't think linearisation of angle $\theta$ is the reason.

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    $\begingroup$ Consider providing more context to this question. Perhaps a diagram that goes with the symbols and the source from which the screenshot is taken. $\endgroup$
    – AJN
    Commented Jan 20, 2023 at 1:58

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Since it's not possible to use latex coding here, I directly uploaded the answer as png. enter image description here

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