1
$\begingroup$

Please I need some help. If I have a driving shaft with 10 Nm torque and 1000 RPM, and I add two 3-inch pulleys on the shaft to transmit power to another shaft with a pair of 6-inch pulleys mounted on it and connected to the initial 3" via a belt, will I have transmitted a total torque of 40 Nm to this new bar at 500 RPM?

Improve this question
$\endgroup$
1
  • 3
    $\begingroup$ torque times speed is constant. You halve the speed and double the torque, so 20Nm $\endgroup$
    – agentp
    Commented Aug 7, 2016 at 20:26

1 Answer 1

Reset to default
1
$\begingroup$

The pulley shaft on the driving shaft is only required to determine the rotational speed of the second pulley on the free shaft. Since the motor can only produce 10Nm of torque, you know the torque and the pulley size is irrelevant.

What agentp was referring to is conservation of energy, meaning in this case the power of your driving shaft is transmitted to the free shaft, assuming no losses.

The power equation is as follows:

Power = Torque x Rotational Velocity

So you can solve for the power of the drive shaft and the rotational velocity. The rules for pulley or gear diameter to speed ratio is:

D1/D2 = N2/N1

Which can be determined by inspection in this case as the pulley with diameter twice as big will logically rotate half as fast.

Then substitute those values into the equation and solve....which results in 20Nm

Improve this answer
$\endgroup$

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Not the answer you're looking for? Browse other questions tagged or ask your own question.