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7

no. The change in moment is zero, as you can see on your plot. I think you can see if you imagine sectioning the beam slightly to the right of the support and constructing a free body diagram, the moment there is not zero. the support does not provide any concentrated moment, so the moment does not change there and so the moment at the support can not be ...


4

The diagram most closely related to the original question seems to be a kinematic diagram. Kinematic diagrams are standardized in ISO 3952, although it seems that most often people are just copying what they have seen without reading the standard (which is quite old, but then this is common anyway). The standard is in 4 parts and covers symbols, and ...


4

This is more of a long comment than an answer as i can not advice any specific software. First, if you intend to do anything professional in print or web productions than yous shouldn't be looking in direction of Microsoft for anything. Much abused does not mean any good. First tier would be to use direct vector drawing apps. In this category you have: ...


3

I had to draw electrical and hydraulic schematics in Microsoft Visio at a past job. I'm glad that is behind me because that software is barely good enough for making flow charts. I would never recommend anyone use it for engineering diagrams. There are expensive professional software programs that solve this problem much better, but if you are on a budget I ...


3

It is a two stage actuator where the triangle represents a pilot. That means that there is a pressure assist. The direction of the arrow indicates the direction of flow.


3

From Tip #16 — What is the condition of your diamonds? Example d), as I’m sure you can easily figure out, is a heater. With all other things being equal, this one shows the inward arrows adding thermal energy to the hydraulic oil. I have left out the coolant flow arrows, which is common, meaning the coolant circuit isn’t specified. Symbol is clearly a ...


3

You are going in the right direction! Lets take these two equations: $$(1) \quad in = \alpha+a_1\alpha z^{-1}+a_2\alpha z^{-2}$$ $$(2) \quad out = b_0\alpha+b_1\alpha z^{-1}+b_2\alpha z^{-2}$$ now rewrite (1) such that it becomes a function of $\alpha$: $$in = \alpha\left(1+a_1z^{-1}+a_2z^{-2}\right)$$ $$\alpha = \frac{in}{1+a_1z^{-1}+a_2z^{-2}}$$ Substitute ...


3

The images references that you have provided look like they could have been produced in LaTeX, possibly using the TikZ package. Have a look at this example http://www.texample.net/tikz/examples/free-body-diagrams/ and this minimal introduction to TikZ to see if it can provide the functionality that you're after! http://cremeronline.com/LaTeX/minimaltikz.pdf ...


2

CAD packages, drawing packages, you can even use shapes in software like Word & Excel, but most book diagrams were drawn by hand (until computers became common) - which explains the profession of draughtsman or draughtsperson to be pc...


2

I think your big misunderstanding is in this paragraph: [...] if I were to scan, starting from the leftmost side towards the right. I would initially see a compressive force onto the beam from R, then, I would see compressive forces (by using the section method at point 1). However once I am coming up to the 20kN force, I would, from my perspective, see a ...


2

Bending moment is the area under the shear diagram which is definitely increasing by a slope of 5kn/m as it gets closer to support in a straight line, so it is maximum on the support. And this moment is balanced by the reaction of roller. If you remove the continuity in beam over the roller and allow a joint there thus removing the moment there, the ...


1

Moment in gerber joint or hinge equals zero, but moment in roller support is not necessarily zero. Moment is double integral of beam load. Reaction force in roller support causes sudden change of moment curve tangent slope.


1

Technically a force on a structure is neither compressive nor tensile. The effect a force has on a structure or the internal reactions can be characterised as tensile or compressive. So in the following example in all cases there is a F force on the right. Then only difference between case A and case B is that in case A the support is on the left, while on ...


1

Conventionally, structural diagrams (V, M, T) are drawn from left to right. In the case of the axial force diagram, we need to set up/state the sign convention then draw the diagram accordingly. (Note that it does not matter where to start drawing, the diagram remains the same, as it must conform to the stated sign convention.) Sign convention: (+) ...


1

In excel what you should do to generate the curve is the following: take all the measurements for the shaft in one column (name it PROFILE) Sort the data column in ascending/descending order (doesn't really matter) Add another column (name it INDEX) with ascending integer (1,2, 3,4 etc) then add another column (name it CDF) and divide the value in the same ...


1

Let's clear the question first: The shear and moment diagrams indicate this is a cantilever beam supported at the left end, and the system is in equilibrium under the applied loads (in green) and the support reactions (in yellow). The range 4<x<7 indicates the internal reactions at a location below the uniform load are in question ("x" is ...


1

Even though I can't find any standardized literature, the theory behind of what you seem to be looking for is the so called systems modelling. Peter E. Wellstead published (can be accessed here: www.control-systems-principles.co.uk) his efforts in "formulating a simple unified approach to system modelling" that could set a framework for handling mechanical ...


1

Given the title of the figure, I'm inferring that the slanted line means "this block adapts slowly based on the given information". The author is probably trying to convey the notion that you could disconnect that slanted input and things would still work -- for a while. Block diagrams are of interest to me because they're very much a living language. I ...


1

Solar Mike is correct (as usual); the block diagram approach is the classic method for "formalizing" the dynamics inside a large and complicated system. However, it is important to realize that this paradigm is of limited utility in analyzing the actual behavior of a big factory in that it fails to take into account the behavior of the humans that manage ...


1

The convention for an idealized spring in such a schematic is that the lateral stiffness is zero but also that it does not move out of its original orientation with respect to its base (i.e., it does not tilt). The idealized spring is characterized by only one parameter: the axial stiffness. (It is thus assumed that the axial deflections are sufficiently ...


1

I am a bit confused here, so I went under the assumption you have a statically undetermined beam with a fixed support (moment resisting) on the left and a roller support (non-moment resisting) on the right. In either case, this method still applied, but the constants become significantly easier in the case where it is a pinned support (non-moment resisting, ...


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