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Assuming the force is placed at a distance L from the support, then the moment of the Force P with respect to the foundation will be $M = P\cdot L$. If the horizontal square tubing tilts by an angle $theta$ then the will be equal to $M = O \cdot L\cdot \cos\theta$ For angle up to 10 degrees, the $\cos \theta$ has a minimal change ($\cos 10^o =0.984$), so ...