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It looks to me like a reed switch (I can't be really sure though because the image is not clear enough). A reed switch is an electrical switch operated (usually) by an applied magnetic field. A common example of a reed switch application is to detect the opening of a door or windows, when used as a proximity switch for a security alarm.


3

The issue is certainly NOT that the chassis ground is at -100V, it's absurd. The chassis ground by definition is at equal potential for power supply and load, you can treat it like one big wire that's large enough to take all the current you could throw into it. If you put a voltmeter between a car's chassis & earth, I promise it will never read -12V. ...


2

Try using a replacing a 9V VDC voltage source with a VAC voltage source. Pay attention to the frequency of the VAC voltage source. This should address the issue. With regard to determining the time value for a particular voltage, review PROTEUS DESIGN SUITE Getting Started Guide. In the section VSM tutorial (Graphs) read around page 230. You might have ...


2

The final value theorem is for a signal, not a transfer function. Use the transfer function to express the output signal $$ V_{\mathrm{out}}(s) = \frac{1}{RCs+1} V_{\mathrm{in}}(s),$$ with input $V_{\mathrm{in}}(s)$. Now, I assume that your input signal is a step-function $$ v_{\mathrm{in}}(t) = \begin{cases}0, \; \mathrm{for} \; t < 0 \\ 10, \; \mathrm{...


2

Try this. Figure 1. A simple snubber indicator. Pressing SW1 will pass a current through L1. D1 will be reverse biased and LAMP1 will remain off. Releasing SW1 will cause L1's top terminal to switch to a negative voltage, D1 will become forward biased and current will flow through the lamp. You can estimate the pulse duration time constant from $ \tau = ...


2

If the switch is ON then the OR gate output will turn on. The NOT gate will not affect the OR gate. If the switch is turned OFF (having been on) then OR will turn off which turns NOT on which turns OR off again and the cycle repeats. The speed of oscillation will be determined by the propagation delay of the gates. Would ... the output end up being analog? ...


1

It is not about density as such. It is about potential or electric field. There is an electric field which applies a force on the electrons from the negative pole to the positive. When connected to ground, at steady state there is no field forcing the electrons from the negative towards the ground. Alternately, to use the potential analogy, electrons at the ...


1

Diode Like you assumed Panels: These are the PV panenls that produce current. They produce DC current I and DC voltage V Inverter: the inverter converts the DC current and Voltage from the panels to AC voltage and current, which is in sync with the Grid. This part is responsible for converting the energy from the panels into the energy that the grid can ...


1

Unless, your point is entirely different, this should be fairly trivial. I'll start from you first equation $$ R\cdot Re\left\{ (\tilde{I}e^{j\omega t})\right\} +\frac{1}{C}Re\left\{\frac{\tilde{I}}{j\omega}e^{j\omega t}\right\} = Re\left\{\tilde{V}_se^{j\omega t}\right\}$$ because, $\tilde{I}, \tilde{V}_s$ are real quantities we can write: $$ R\tilde{I}\...


1

The pneumatic circuit in your question provides simple start / stop control of the piston. While the 5-port valve is opened you have full flow in either forward / reverse directions. Your control logic would monitor piston position as it approaches a target, then close the 5-port valve when position is within tolerance. This is accurate enough for some ...


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