# Tag Info

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Radians and unit analysis The comment by MrYouMath is correct. For the purposes of dimensional analysis, the radian is considered a dimensionless quantity and therefore does not need to be included. This is because the radian is defined by an arc length (L) divided by a radius (also L) to give (L/L). The units of the Laplace domain complex number, $s$, are ...

5

I thought I would expand a little on the answer offered by Karlo. Long story short, I would not try to calculate the analytical time response of a system to a square wave. That would be a serious pure-maths exercise, and not necessary for most engineering applications. Instead, I would suggest using the step response analytical vs. simulated to validate ...

4

A bimetallic strip is used. Two different metals like steel and copper expand at different rate and a strip of the two bound together as result bends with temperature changes. A contact placed at the end of the strip will close when the temperature is right - and the temperature can be tuned by turning a screw that pushes the strip closer or farther from the ...

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R2 and RL are in parallel so the voltage across them will be the same so can be treated as a single resistor when thinking about the voltage across them. So Req(lower) = (1/R2 + 1/100kohms)^-1 Req(upper) = (1/R2 + 1/200kohms)^-1 Vs/(R1 + Req) = I Hopefully this gets your started, you're looking to produce a system of 2 equations that you can use to ...

3

The issue is certainly NOT that the chassis ground is at -100V, it's absurd. The chassis ground by definition is at equal potential for power supply and load, you can treat it like one big wire that's large enough to take all the current you could throw into it. If you put a voltmeter between a car's chassis & earth, I promise it will never read -12V. ...

3

Your understanding of the issues is good. Q1: It's not overkill at all. All of the elements you've mentioned are needed. Q2: The low-pass filter frequency needs to significantly attenuate all frequencies above 1/2 the sampling frequency. It makes sense for a 'low fi' arrangement to reduce the filter frequency a bit so as to simplify filter design which ...

3

My input is DC from a small DC motor which I use as a generator. My input current is 300 milliamps and I need 1200 milliamps as output. Is there some way to increase the output to 1200 milliamps ? With out using external energy input you can transform voltage or current but you can not increase the power level. As power = voltage x current, that means,...

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If you are trying to get from 6VDC or 10VDC up to 16VDC, you can use a boost converter, and if you're trying to get from 24VDC to 16VDC you can use a buck converter or a "linear regulator". The Wikipedia pages I've linked you to will explain everything in more detail, but briefly, a linear regulator works by "burning off" the extra voltage in the form of ...

2

You want to look for the Laplace transform of a square wave. Note: The transfer function $H(s)$ is the ratio of the Laplace transforms of output $Y(s)$ and input $U(s)$: $Y(s)=H(s)\cdot U(s)$ If you take the Laplace transform of a function (input our output), it is not called a transfer function.

2

Assuming that you have an $RLC$ circuit, the resonant frequency will be $$f_0 = \frac{1}{2\pi\sqrt{LC}}$$ so, theoretically, you can pick either $L$ or $C$ arbitrarily and then calculate the other for a given resonant frequency. Unfortunately, you want circuits that are resonant at low frequencies. For reasonable values of $C$ you will need very large $L$....

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First off, neural networks are only very rarely done in hardware, as actual summation of electric signal. Much more often they are just programs that run on standard computers, simulating a network with numerical inputs and outputs, and when you want superior speed and size, you implement it in hardware of FPGA, but still with numerical input and output. ...

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To make sure the inductor will respond that fast, you need to solve for the size of the inductor (which will make your magnetic field) which will be resonant at 1000Hz when coupled with a capacitor of convenient size. luckily, an old-school stereo speaker containing a woofer and a midrange speaker will contain a crossover network which has in it an ...

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The following pins appear to be pogo pins or spring loaded pins Below are example of pogo pins The following appear to be swage mount connectors Here is an example Reference: Mill-max How to pair the Retekess SU-668 Restaurant Paging System

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If the switch is ON then the OR gate output will turn on. The NOT gate will not affect the OR gate. If the switch is turned OFF (having been on) then OR will turn off which turns NOT on which turns OR off again and the cycle repeats. The speed of oscillation will be determined by the propagation delay of the gates. Would ... the output end up being analog? ...

1

Diode Like you assumed Panels: These are the PV panenls that produce current. They produce DC current I and DC voltage V Inverter: the inverter converts the DC current and Voltage from the panels to AC voltage and current, which is in sync with the Grid. This part is responsible for converting the energy from the panels into the energy that the grid can ...

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As indicted in the comments usually the VDC for traditional automotive is 12 VDC nominal, though in most cases it is 14 VDC. Looks like the below image is from a similar configuration. If the part number for the 6 PIN TSOP can be identified this could help get closer to your goal. Other observations, this 98-0344 motor driver on the board has a dot over ...

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In this circuit: The gain from Vin to Vout2 is about 1, and to Vout1 about -1. That the two gains have the same magnitude with opposite sign can be deduced from the fact that at first approximation, the emitter and collector currents are equal. Since the emitter and collector resistors are the same, the voltage changes across them due to the same current ...

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It is perfectly possible to build your own mixed circuit chip, but you will indeed need to learn quite a few things if you want to do it by yourself. First I would like to say that what you will do is not a drag and drop but a place and route If you want to do it by yourself, here are the steps to follow: Determine the technology you want to use, if you ...

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Try a bi-stable lock/unlock mechanism per drawer. A solenoid or perhaps two flip the state of the lock. No power is needed to stay in any one state, only to flip states. Since the solenoids only need to be run for a short time, like maybe 50 ms, the large current spike can be supplied locally by a capacitor. That capacitor can then charge up more slowly ...

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don't know whether you resolved this. Answer: Your part has one of the lowest over current thresholds (60mV in table), pick a higher voltage. Unfortunately I can't see how the voltage translates to current in the datasheet so you will have to base it on the measured cutoff current from the original part. Also did you ever perform a battery discharge test and ...

1

AFAIK generate your 4kV using off the shelf components. The trick is getting the electrons off the wire, and into the air. Sharp points are your friend here. An electron at the tip is repelled by all electrons on the surface of the point behind it. In practice, the more common practice is to use a very small diameter wire. The tight radius of the wire ...

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Control/Automation engineer here. I think it's highly unlikely that you will ever need to design a semi-conductor chip. In my experience the vast majority of Automation/Control jobs are based on PLCs, VFDs, PID Controllers, sensors, and relays. Even custom circuit boards are rare unless you're building something very exotic. Even with high tech equipment ...

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I had this same question but was able to solve it. I've attached a picture of my circuit. I know this was asked but I hope this helps someone. The Supply rail is attached to the rippled power supply. Whether it's stable or rippled doesn't affect the functionality noticeably (as long as it's above the minimum Supply)

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I believe you are describing a charge pump. You don't give any specifics on what you're trying to do, though, so I can't really give meaningful feedback on anything else. Generally speaking, though: I am looking to capture as much energy as possible from a small steam turbine using a DC motor and then use that to power another DC motor. If you're ...

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It is possible that the outlets you want to pair together may have the same supply : relay and / or fuse... You should connect a set of wires with appropriate fuse directly to the battery, if this is for short periods of use otherwise you will end uo with a flat battery. The best solution is to fit a second battery, run the inverter from that and have a ...

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Okay, I will go ahead and answer my own question. Since I'll have to deal with an analog signal anyways, coming from the audio output of a mobile device. I'll need an ADC [analog to digital converter] then I'll match that up with a DAC [digital to analog converter] and send that out a TRS plug. This thing will need it's own power supply for it all but I ...

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I believe the voltage source you are looking for is Vsin, which is just a sin wave output. Aside from that as the other answer mentions only use one ground!

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3.4 µH is not a standard value, but 3.3 µH is. There are plenty of those out there, even in thru-hole. Inductors aren't generally accurate enough to justify making a 3.4 µH version when a 3.3 µH version is already in production. The extra 3% more isn't worth another product to manufacture, and for customers isn't worth another part ...

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Correct - putting inductors in series will result in an effective inductance equal to their sum. The problem is the extra wiring, and/or change in the wires' paths. Moving two wires closer together makes them act like a small capacitor. Long wires act like a resistance, and (obviously) loops act like inductors. 3.4uH is relatively large, so you might not ...

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