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@Transistor although this is not a response (because the problem was IMHO the positive direction), the following is rendered much better here, and its a different approach to the same problem. $$h_A = …

I think the main thing that is confusing you is the following, is that you think that there is an option for the positive rotation. While in some cases this is true, since you deciced on employing the …

I suspect this book is related to motion dynamics. The reason why it states that angular measurements are in radians only, is probably because it tries to avoid confusion and ambiguity. The problem is …

There is no need to know the mass of the block. If it were movable yes, but in this case you can assume that is a fixed wall. So the whole idea is that you are assuming a constant (average) decelerati …

Actually, when you are accelerating you are not pushed back, instead you are pushed forward. Initially, you are travelling with the same speed with the car. if the speed is constant then there is no h …

If I understand the problem the you have: a mass moving at 10[m/s] at time t=0, a force of 30 [N] is applied, and by time t=2 it increases to 130 [N] The question is what is the final momentum. The …

In order to solve the problem you need the following equations: equilibrium along the x-axis $$T\cos\theta = m \cdot a_{Cx} $$ equilibrium along the y-axis $$T\sin\theta - m g= m \cdot a_{Cy} $$ …

First of all I would try to determine the angle that link 3 forms with the horizontal. This can be easily determined because: $y_A = l_{A0-A}\cdot \sin(45^o)= l_{A0-A}\cdot \sin(\theta_B) $ Where : $\ …

In general you are right. It's not possible to casually add position vectors in different coordinate systems. However in this case it is possible, because of the context. In order to help you understa …

After verifying the values for angular velocity ($1.25 \left[\frac{rad}{s}\right]$)and acceleration ($-1.56 \left[\frac{rad}{s^2}\right]$), I calculated the $\vec{v}_G$ the velocity of point G. $$\v …

Given the geometry of the object, the center of gravity is very close to the surface between the cylinder and the cone. More specifically the distance between the center of gravity and the base of the …

I'll be using subscript notation $_2$and $_4$ to denote the mass with 2 kg and 4 kg respectively. Also note that $a_2$ and $a_4$ both point upwards which I consider as the positive direction. There a …

Something that might help you clear this is the following sketch. I just drew the forces in the direction that they will allow the rope/wire to be taut. In your original sketch the directions of the …

In order to find the acceleration the process is similar to this question. For the inertial observer the angle of the acceleration ($\phi$) with the horizontal axis will be steeper than the angle of t …

The following is a side and a top view of the problem (hopefully you understand the sketch). the green is the pole and wire the red is the circular motion trajectory the black are the forces. with l …