5
$\begingroup$

With linear bearings, could they be used to join one rod with another to form a cross-junction and rotate with around a 0.3N-mm torque? Suppose the rods are fairly thin, eg, 5mm in diameter. That is, could linear bearings bear a radial load? Would the bearings deform?

UPDATE Here's a diagram

enter image description here

Suppose the blue rod is attached to a gear driven by a motor. The blue rod itself is also attached to the bearing's housing. The blue essentially rotates and drives the black, exerting force/stress on the bearing. The idea is to mount a slidable camera on the black which can be rotated by the green gear.

Improve this question
$\endgroup$
6
  • 1
    $\begingroup$ The point of linear bearings is that they do not resist axial loads, they slide axially and only resist radial loads. $\endgroup$
    – Ethan48
    Mar 22, 2016 at 22:54
  • $\begingroup$ I'm not sure I understand what configuration you're describing, can you sketch it for us? $\endgroup$
    – Air
    Mar 22, 2016 at 23:01
  • $\begingroup$ @ethan48 sorry, by axially I actually meant radially. That is, whether turning a linear bearing radially would deform or damage the bearing. $\endgroup$
    – Kar
    Mar 23, 2016 at 0:26
  • 1
    $\begingroup$ @Air Sure. I've added a diagram to my OP. $\endgroup$
    – Kar
    Mar 23, 2016 at 1:22
  • $\begingroup$ OK, got it. The blue rod will be able to spin along with the red bearing while the black rod stays stationary. The blue rod will also be able to move back and forth along the length of the black rod. Is that what you're asking? $\endgroup$
    – Ethan48
    Mar 23, 2016 at 1:31

1 Answer 1

Reset to default
1
$\begingroup$

The bearing should have figures on the moment loads it can take. Failing that, use two bearings and allow them enough movement so effectively each is just supporting a purely radial load.

Improve this answer
$\endgroup$

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge that you have read and understand our privacy policy and code of conduct.

Not the answer you're looking for? Browse other questions tagged or ask your own question.