I open the door for 30s of a 140L capacity 80W (240VAC, 0.8A) barfridge with a 20L freezer compartment (partition open to main compartment at one end) at a temperature of -5℃ with an internal main compartment temperature at 2℃, with initially 30L of 50-50 glass and plastic containers container mainly water inside, in a room at an ambient temperature of 41℃ and 85% humidity (Sydney today), to take out a 6-pack of medicinal beer.
Presumably, the cold, denser air from inside the fridge flows out, and is replaced by the hot, lighter air from the room.
How much of the fridge and freezer compartment air is exchanged in that time period?
How long does it take the exchanged air in the fridge to equilibrate to its initial temperature of 2℃? What equation describes this? Is there an initial temperature rise?
How many grams of ice will precipitate from the exchanged air into the freezer compartment?
EDIT UPDATE
After @Chris Johns' answer, I rolled the barfridge out and actually looked at the manufacturer's plate, and then updated my question from my original eyeball estimates.
Changed 40L to 140L
Added power info: "80W (240VAC, 0.8A)".
From my calculations, $ P = V_{rms} * I_{rms} $ = 240VAC * 0.8A = 192 W,
so efficiency, $ \eta = P_{out} / P_{in} \%% $ $ = {80W \over 192W} = 41.7\%% $
Changed freezer compartment capacity eyeball estimate from 10L to 20L
The refrigerant is $CCl_2F_2-R12$, 85g.
Clarified the internal contents of the fridge as containing a total of 30L of plastic and glass containers (50-50) containing mostly water.
Clarified the temperature of the freezer compartment at -5℃.
I presume you can calculate the coefficient of performance (CoP) from this data?