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Since all it really is is a heating element, what happens if I use a 240v/50Hz clothes iron with a 110v/60Hz supply?

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    $\begingroup$ Be careful: if it's a fancy-schmancy iron with tilt sensors, auto-timeout, etc., you might make the low-voltage electronics unhappy. $\endgroup$ – Carl Witthoft Nov 30 '15 at 12:22
  • $\begingroup$ You might, although if it is fancy-schmancy, it is very likely the low voltage power supply is done right and will do its job both for 110V and for 230V... $\endgroup$ – 50k4 Nov 30 '15 at 15:37
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In general, anything with a heating element will produce only 1/4 the heat on 1/2 the voltage, since power is proportional to voltage squared.

In other words, you'll probably be disappointed with the results.

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  • $\begingroup$ P = IV so why the 1/4 to 1/2 ratio? $\endgroup$ – Steve Lorimer Nov 30 '15 at 2:14
  • $\begingroup$ With a constant resistance, when you halve the voltage, you also halve the current. $\endgroup$ – Dave Tweed Nov 30 '15 at 2:21
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    $\begingroup$ @SteveLorimer - It's P = V^2/R variant in this case, not P = VI $\endgroup$ – user16 Nov 30 '15 at 2:56
  • $\begingroup$ @GlenH7 Both formulae apply. One is more obvious than the other. Also P = I^2 x R. With half voltage you also get half current as I = V/R. Plugging in both I & V figures as approriate gives the same results with all 3 formulae. $\endgroup$ – Russell McMahon Nov 30 '15 at 12:43

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