0
$\begingroup$

I posted this question in physics, but they advise me to post it here so here I am.

I was looking for the formula to calculate the burden in bench blasting and I found this document. The problem is I have to calculate the concentration of the charge first with the unit kg/m. I know that some materials are given but I need the formula to calculate other materials in which I have their energetic values calories/g calories/cm3 ..

$\endgroup$
6
  • $\begingroup$ This document might be interesting: Explosive Engineer's Guide. $\endgroup$
    – Fred
    Commented Nov 9, 2023 at 6:19
  • $\begingroup$ My understanding is the charge concentration, I$_b$ is the mass of explosive divided by the length of hole that contains explosive. $\endgroup$
    – Fred
    Commented Nov 9, 2023 at 6:23
  • $\begingroup$ This seems to be a units issue, not an engineering issue. $\endgroup$
    – Solar Mike
    Commented Nov 9, 2023 at 6:42
  • $\begingroup$ @SolarMike: For those who don't know anything about explosives engineering & blasting, it's not a units issue. If anything, it's more of a terminology issue. The units at the end of the text are not important to what is being asked. $\endgroup$
    – Fred
    Commented Nov 9, 2023 at 9:05
  • $\begingroup$ @Fred sure it is terminology issue no doubte on that, so since it is mass per distance can it be the velocity or pressure? $\endgroup$
    – Tintin
    Commented Nov 9, 2023 at 16:28

1 Answer 1

1
$\begingroup$

The charge concentration, in kilograms per meter of drill hole, serves two purposes. The first is being able to determine the amount of explosives needed to blast a given amount of rock. This is needed when ordering explosives from the supplier or when taking out enough explosives from the magazine.

$M_{Explosives} \ = \ I_b \cdot N \cdot (L_H \ - \ L_S)$

Where:

  • $M_{Explosives}$ is the mass of explosives required [kg]
  • $I_b$ is the charge concentration [kg/m]
  • $L_H$ is the length of the drill holes [m]
  • $L_S$ is the length of the stemming [m]
  • $N$ is the number of drill holes

The other purpose of the charge length is, if one knows the energy equivalent of each type of explosive [J/kg], for its given density of explosive, it becomes possible to calculate the amount of energy expended in the blast by the explosives used.

$\endgroup$
10
  • $\begingroup$ first thank you for the time you have gived to answer my question i apreciate that, so lets say the material is TNT it has 1.65 g/cm3 and 4.184 MJ/kg can you please add that as an example in your answer thank you again. $\endgroup$
    – Tintin
    Commented Nov 9, 2023 at 21:30
  • $\begingroup$ When you say "The charge concentration, in kilograms per meter of drill hole" you mean X kilograms multipied by numbers of meters deep of the hole? For example if the charge concentration is0.3kg/m TNT and a drilled hole is 7 meters deep stemming excluded this gonna equal to 0.3×7 = ~ 2.1 kgs total per one hole. $\endgroup$
    – Tintin
    Commented Nov 10, 2023 at 14:13
  • $\begingroup$ @Tintin: Regarding your last question with a charge concentration of 0.3 kg/m & a 7 m long hole, yes the mass of explosive in the hole would be 2.1 kg. $\endgroup$
    – Fred
    Commented Nov 10, 2023 at 19:14
  • $\begingroup$ @Tintin: TNT is not a good example of an explosive to consider. It's basically a military explosive & rarely used for civil or mining purposes. It is mixed with other explosives as a compound, but I'm unaware of it being available as sticks. For surface mining & quarries ANFO or emulsion explosives are more likely to be used. $\endgroup$
    – Fred
    Commented Nov 10, 2023 at 19:21
  • $\begingroup$ Thank you very much Fred that was very informative. $\endgroup$
    – Tintin
    Commented Nov 10, 2023 at 19:40

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Not the answer you're looking for? Browse other questions tagged or ask your own question.