0
$\begingroup$

I am trying to optimize the angles alpha and theta, for which members of truss would carry the less loads. Given is location of force and value of force.

Problem is, that I get contradictory equations, where decrease of one angle is favorable for one member but unfavorable for other one (as more vertical member gets, more vertical loads it will carry). So I came up with the equation, but I am unable to solve it for angles to get minimum force values in the members.

On one hand, I know that it has something to do with derivatives, because if we set derivative of force with respect to angle to zero, I think one should be able to get the most efficient angle. But, there are 2 equations and I am not sure if this approach is correct or how to set up derivative equation.

Any ideas you may suggest?

Thanks.

I am attaching the drawing of the truss structure below

enter image description here

$\endgroup$
6
  • $\begingroup$ I assume $L_1$ and $L_2$ are constants? or is the length of the rods constant? $\endgroup$
    – NMech
    Jan 15 at 15:22
  • $\begingroup$ I changed the task and refined it a little bit. What is given is $ L_{3} $ and $ F $ , idea is to find optimal angles with absolute value of $ F_{AB} + $$ F_{BC} $ is minimum. $\endgroup$ Jan 15 at 17:07
  • $\begingroup$ Is also H constant? $\endgroup$
    – NMech
    Jan 15 at 17:17
  • $\begingroup$ No, $H$ is the height, which is defined by the angles and $L_{3}$ as shown in equation 3 in the Geometry part of the Figure attached. Only known quantities (constants) are $F$ and $L_{3}$, angles are to be found and all other geometries, as well as internal forces in members are defined by angles. $\endgroup$ Jan 15 at 17:50
  • 1
    $\begingroup$ It's an underconstrained solution, you'll minimise the axial forces by maximising H, ad infinitum. Both will tend to F/2. $\endgroup$ Jan 15 at 21:59

0

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge that you have read and understand our privacy policy and code of conduct.