Consider a SISO non-linear system $$\dot{x} = F(x,u)$$ in which $\vec{0}$ is an equilibrium point. In the process of determining that it is indeed an equilibrium point, the input did not matter at all. It was completely independent, due to the term $x_4 \cdot u$
- $u(t) \in \mathbb{R}$ is the input
- $x_4$ is a state variable
I want to linearize the system about $\vec{0}$. But I haven't completely understood the theory behind it, and I would appreciate some help.
1. Can I completely ignore the term $x_4 \cdot u$, i.e. consider it as a higher order term, as we would do for example with 2 state variables $x_1 \cdot x_2$?
If so problem solved.
2. According to the theory, when I want to bring the system to the linear form $$\dot{x} = A x + B u$$ then $$A = \frac{\partial{F}}{\partial{\vec{x}}} \text{ calculated at (0,u*) i.e. at the equilibrium point}$$
However, in the system I am examining we cannot extract any information about u*. What would even u* mean in this system?
Thanks for your time. If you can provide an answer to the 1st question I think I would be ok.
EDIT: The system equations are $$\dot{x_1} = x_2$$ $$\dot{x_2} = \frac{2x_2 + \sin(x_1) + x_3 x_2^2}{1 + x_1^2} + x_3 $$ $$\dot{x_3} = x_4$$ $$\dot{x_4} = 3x_4 + u \cdot x_4 + 2x_3^2 +x_1^2 x_3^2 + \sin(x_2)$$