in the figure below the reaction torque equation is given by Fg41.x trying to rock the ground plane about the O2 pivot due to gas forces . My question is if the piston with the cylinder whole assembly were shifted down by a distance L as shown in figure , will the horizontal (Fg) force contribute to the reaction torque equation ? Because this gas force was not creating a moment in the first case since its moment arm was passing through the pivot , but now after shifting L distance, a moment vertical arm is in present i.e. (T12 will now become = Fg.L+Fg41.x) , is that true?
Here is a figure that may help you understand me.
In this case in the figure with an offset length=L won't the gas force acting on the wall of the cylinder (Fg41x * L) generate a moment about O2 pivot which will try to rock the cylinder ground link 1 around this O2 pivot? and thus the total gas torque would be the torque in the first case (were the Fg41x moment arm was passing through the pivot and thus produce no moment) + the new generated moment from Fg41x?