Can I draw this part of kinematic diagram in this way, knowing that bolded W is a point of interest. so is my drawing true also? (my lines are in red and black(no
t bolded black))?
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$\begingroup$ are you asking if you can draw the red line freehand, or if you need to use a ruler? $\endgroup$– jsotolaNov 4, 2021 at 22:34
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$\begingroup$ if the only forces are vertical you can estimate the device by leaving out vertical dimensions. But if there are any other forces, including moments, you need to draw it according to actual. $\endgroup$– Tiger GuyNov 4, 2021 at 23:15
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$\begingroup$ @Jastola. I'm asking if my drawing is a true drawing instead the one drawn already (not about ruler it's about the way of drawing(location of joint and triangle) $\endgroup$– Jesse FlynnNov 5, 2021 at 12:03
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$\begingroup$ @tiger guy so at the end is my alternate drawing true? $\endgroup$– Jesse FlynnNov 5, 2021 at 12:07
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Don't look correct to me. Are you trying to draw the displacement diagram?
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$\begingroup$ Yes exactly . since L5 is directly connected to horizontal link 6 I connected them directly but what the book did is what you can see taking an inverse triangle of mine. Once you've drawn a line between link 5 and JOINT D it may look like another joint . $\endgroup$ Nov 5, 2021 at 19:13
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$\begingroup$ Unless something is hidden, the book is wrong, because the bar L6 is an integral piece without breaking at D, and the small plate D is welded to L6, so while L5 can push and rotate about the pin at D, it can't bend L6 to form the kink as shown. Or, is L6 a much weaker material? $\endgroup$– r13Nov 5, 2021 at 19:29
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$\begingroup$ not at all . same material . Thank you my brother for your help $\endgroup$ Nov 5, 2021 at 21:47