# Motor Power for vertical lift in linear slide mechanism

I want to pull up and down 10 kg metal cylinder at 7 inch vertically by using linear slide mechanism in 1 second. What should be the motor rpm, gear type, torque, watt etc? Otherwise how to calculate all those things? Thank you very much!

• Why do you mix the metric with the standard? Sep 28 at 19:30
• @StainlessSteelRat metric is standard. Much prefer using Watts to btu… Sep 28 at 20:08
• @SolarMike They tend to complain if I say English! Something about a colonial war! Sep 28 at 20:15
• @StainlessSteelRat I referred to it a screw as an imperial screw once and they got super offended and said why wouldn't I just refer to it as an inch screw. Sep 29 at 16:53

Let's convert 7 inches to meters, 7x0.0254 = 0.1778m

You need a motor that can produce an average speed of 0.1778m/s so it must have an acceleration of 0.1778*2= 0.3556m/s^2

Now we can calculate the force your winch or motor needs. it must lift the 10kg against gravity and accelerate it

$$F = m \alpha+ mg= 10kg*0.3556m/s^2+10kg*9.8m/s^2 =10*10.155m/s^2$$

$$P_{average}=\frac{F*0.1778}{t}=101.5kgm/s= 9.81 * 101.5=995.715watts$$ I will detail the size of pulley later.

• An improvement might be to convert kgm/s into something useable. Sep 28 at 20:49
• right, @Tiger Guy. i will. Sep 28 at 21:10
• Thank you very much!
– XO56
Sep 29 at 18:37
• If you are happy with the answer you should accept it, but there is also a benefit to waiting a couple of days (especially on this Stack), to see if there is a better one. Sep 29 at 20:42