0
$\begingroup$

I want to pull up and down 10 kg metal cylinder at 7 inch vertically by using linear slide mechanism in 1 second. What should be the motor rpm, gear type, torque, watt etc? Otherwise how to calculate all those things? Thank you very much!

$\endgroup$
4
  • $\begingroup$ Why do you mix the metric with the standard? $\endgroup$ Sep 28 at 19:30
  • 1
    $\begingroup$ @StainlessSteelRat metric is standard. Much prefer using Watts to btu… $\endgroup$
    – Solar Mike
    Sep 28 at 20:08
  • $\begingroup$ @SolarMike They tend to complain if I say English! Something about a colonial war! $\endgroup$ Sep 28 at 20:15
  • $\begingroup$ @StainlessSteelRat I referred to it a screw as an imperial screw once and they got super offended and said why wouldn't I just refer to it as an inch screw. $\endgroup$
    – DKNguyen
    Sep 29 at 16:53
1
$\begingroup$

Let's convert 7 inches to meters, 7x0.0254 = 0.1778m

You need a motor that can produce an average speed of 0.1778m/s so it must have an acceleration of 0.1778*2= 0.3556m/s^2

Now we can calculate the force your winch or motor needs. it must lift the 10kg against gravity and accelerate it

$$F = m \alpha+ mg= 10kg*0.3556m/s^2+10kg*9.8m/s^2 =10*10.155m/s^2$$

$$P_{average}=\frac{F*0.1778}{t}=101.5kgm/s= 9.81 * 101.5=995.715watts$$ I will detail the size of pulley later.

$\endgroup$
4
  • $\begingroup$ An improvement might be to convert kgm/s into something useable. $\endgroup$
    – Tiger Guy
    Sep 28 at 20:49
  • $\begingroup$ right, @Tiger Guy. i will. $\endgroup$
    – kamran
    Sep 28 at 21:10
  • $\begingroup$ Thank you very much! $\endgroup$
    – XO56
    Sep 29 at 18:37
  • $\begingroup$ If you are happy with the answer you should accept it, but there is also a benefit to waiting a couple of days (especially on this Stack), to see if there is a better one. $\endgroup$ Sep 29 at 20:42

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.