The tensile test specimen used for tension test has an enlarged cross sectional area at the ends. The sources I'm referring to, suggest that this is the case so that the failure occurs in the central region of the specimen where the stress distribution is uniform and is more easier to calculate (using P/A).
Now, what I conclude is that if the c/s area of the specimen were to be uniform throughout the length, failure would've occured near the ends where the stress distribution was non uniform, and that is the reason why we increase the area near the ends so that failure doesn't occur near the ends. My question is if the c/s area were to be uniform throughout the length why the failure occurs near the ends?
I mean if we are enlarging the ends, we would've been doing so because failure is occuring near the ends (with uniform c/s), so we're trying to avoid that by enlarging the ends.
If what I have written isn't making sense, then if anyone could explain what would've been the problems faced with a uniform c/s area specimen, that would be enough too.