2
$\begingroup$

I have been reading about the elasticity of materials and most often in engineering there is always some ideal concepts which are the extreme cases. So is there any particular definition to what is a perfectly elastic and perfectly plastic material?

Perfectly Elastic Material

A lot of people say that from material science point of view a more elastic material means the material has greater resistance to elastic deformation eg steel being more elastic than rubber . With that definition ,a perfectly elastic material should then be defined as " a material which suffers zero deformation under any value stress (within elastic limit)". But in this case it becomes similar to the definition of a rigid body , which is "a body that suffers no deformation under stress".

Yet another possible definition could be that a perfectly elastic material is one which behaves as an elastic material over its entire stress-strain curve i.e behaves as an elastic material till fracture. Here then we could have perfectly linear elastic material and perfectly non-linear elastic material.

Perfectly Plastic Material

A perfectly plastic body could be defined as one which produces no restoring force for any value of stress applied. Thus a perfectly plastic body would always suffer permanent deformation for any value of load applied or in other words a perfectly plastic body would show plastic behaviour throughout the stress-strain curve.

If perfectly plastic and perfectly elastic are well defined ,how would their stress-strain curve look like?

$\endgroup$
5
  • $\begingroup$ WOuldn't the stress-strain curve for a perfectly plastic just be a horizontal line at zero while the perfectly elastic just be an straight line increasing to infinite? Of course, perfectly rigid would be a vertical line at zero. $\endgroup$
    – DKNguyen
    Aug 11 at 4:10
  • $\begingroup$ In the case of perfectly elastic by straight line you meant an inclined straight line right? Well it could be straight line or a non linear curve (since elastic bodies can be linear or non linear). But in the case of perfectly plastic there is a bit of confusion as to how its defined. Here is a link. The answer by philip howie doesn't consider it as a horizontal straight line right from the zero strain condition. In that answer elastic deformation is still occurring for a perfectly plastic material. $\endgroup$ Aug 11 at 4:37
  • $\begingroup$ But he does make a difference between perfectly rigid plastics and elastic-perfect plastic. Also what would be the young's modulus in these cases? $\endgroup$ Aug 11 at 4:40
  • $\begingroup$ Errr yeah. SOme finite slope, between zero and infinite but not including them. But I think I also mixed up yield and plastic regions above. When you said perfectly elastic I of interpreted it as always yielding. $\endgroup$
    – DKNguyen
    Aug 11 at 4:54
  • 1
    $\begingroup$ The perfect elastic material will break within the elastic range (stress vs strain is linear represent by a straight line), its failure is brittle without plasticity. On the other hand, the perfect plastic material does not possess linear elastic behavior, the deformation is large at low stress, and the stress vs strain relationship is non-linear represent by a curve. $\endgroup$
    – r13
    Aug 11 at 6:11
4
$\begingroup$

If I understood correctly you are only after the stress-strain curves.

enter image description here

Figure: Stress strain curves for different types of materials (source What's pipping)

  • Perfectly Elastic : (referred to as Linear Elastic) returns to its original shape, and the force is proportional to the deformation (definition may vary)
  • Perfectly plastic : (referred to in the image as Rigid Perfecly Plastic): A material that does not produce a restoring force after deformation.

Additionally, two other types of materials are presented:

  • The Elastic-Perfectly Plastic which is a common simplification for materials that deform up to a point elastically, then deform plastically, and only partially return to the .
  • the Visco-elastic where the force is depended on the strain rate.

The problem is that in most cases these models, don't necessarily represent a real material, so there is an confusion in the literature depending what you are looking at.

Usually the elastic refers to either:

  • the relationship between the proportional relationship between stress and strain
  • the ability of the material to return to its original form/position

Usually the plastic refers to a material that retains all or some of the deformation.

$\endgroup$
12
  • $\begingroup$ What does rigid-perfectly plastic mean? A rigid body is said to non-deformable under any stress. $\endgroup$ Aug 11 at 4:45
  • $\begingroup$ The Rigid-perfectly plastic label came with the picture, that I didn't want to change since I got it from another reference. In my interpretation, Rigid does not make sense. That's why I added the parenthesis " (referred to in the image as Rigid Perfecly Plastic)" $\endgroup$
    – NMech
    Aug 11 at 4:49
  • $\begingroup$ Then we could say that a perfectly elastic body can have any value Young's modulus. While for rigid body it is infinite and for perfectly plastic it would be zero. $\endgroup$ Aug 11 at 5:00
  • 1
    $\begingroup$ @r13 I thought Young's modulus is only defined for elastic region (linear) of material. For plastics region we don't define it not because of that fact that it is non-linear but because Young's modulus is only applicable only to linear elastic region. If a material doesn't have elastic region then I think we could take Young's modulus as zero. $\endgroup$ Aug 11 at 6:09
  • 1
    $\begingroup$ @r13 That is in the case of elastic plastic material i.e the practical cases. Whatever elastic strain you have induced in it would be recovered and plastic strain remains as it is once stress is removed. In perfectly plastic there is no elastic strain occurring. $\endgroup$ Aug 11 at 17:52
1
$\begingroup$

I believe the answer to this question depends on what kind of perspective you use. I won’t get into details on the two materials type as they have already been well described in other replies. I will focus on what is my point of view on this:

  • from an engineering standpoint I believe the two materials make sense. In the way that stress applied to the material are well within its elastic region thus it behaves as a perfect elastic material. Imagine bending a steel H beam with few Newton, the response is basically perfect elasticity. In a simile way if you load it with multiple tons then you will be analyzing something good similar to perfect plasticity

  • from a material science point of view then I think it makes less sense if not for modeling purposes

$\endgroup$
1
$\begingroup$

This is not to answer your questions but the comment on the modulus of a material in the plastic range, which I consider is undefined rather than zero because both the stress and its increment are non-zero.

The upper graph is the stress-strain curve of rubber. The lower graph is the stress-strain curve of silicon rubber. (Note the line between the two points of interest is idealized as straight)

enter image description here

ADD: I suggest reviewing the practice and reasoning of using the "Offset Method" to determine the "yield point" for some ductile materials. (While it differs, as it is well defined, from the case I've shown, which is not defined and accepted by the engineering community, the concept is similar - a modulus relating stress and strain can be defined in any region along the curve if needed, and it wouldn't be "zero" unless the increment of the stress is zero or negative.)

enter image description here

Offset Yield Method

ADD: Unrelated to my writeup here, but provided for your information - "Perfect plasticity is a property of materials to undergo irreversible deformation without any increase in stresses or loads."

$\endgroup$
5
  • $\begingroup$ I have seen in many posts where people take the tangent or secant modulus as the modulus of elasticity in case of non-linear elastic region. Yep I think we could still consider the slope of curve at each point (in plastic region) to maybe show the resistance to deformation in plastic region i.e strength of material in plastic region. But either way it wouldn't affect the young's modulus. I still don't understand how it makes sense to say that a perfectly plastic material has zero Young's modulus when it clearly doesn't have an elastic region. I guess I will ask it as another question maybe. $\endgroup$ Aug 13 at 13:18
  • $\begingroup$ "I still don't understand how it makes sense to say that a perfectly plastic material has zero Young's modulus when it clearly doesn't have an elastic region." It does not make sense and is incorrect. See this toppr.com/ask/question/… $\endgroup$
    – r13
    Aug 13 at 16:31
  • $\begingroup$ I don't believe those sites because there is a lot of different answers like here ,the same site also has contradicting answer. These are answered by various people in community. Answers from such sites is actually what dragged me to onfusion. $\endgroup$ Aug 13 at 17:07
  • $\begingroup$ It was provided for fun surely not serious. For "perfect plasticity", my interpretation is - a substance will undergo deformation by its own weight, a fluid-like material, which services no engineering purpose, but hypothetical representation. for the field that mainly deals with strength and deformation. As opposed to the solid materials, in a coordinate system, the stress-strain curve of such substance will lie in the second quadrant, in which, the viscosity is more of an interest and proper word to define it. Hope this makes sense to you. $\endgroup$
    – r13
    Aug 13 at 17:35
  • $\begingroup$ The "fun" link delivers a very important message that every engineer holds dearly - "Young's modulus is only defined for the elastic part of the stress-strain curve. So for a plastic body, it wasn't defined. Please read this article too. byjus.com/physics/youngs-modulus-elastic-modulus As your confusion seems to be caused by the persistence of linking Young's modulus to the plastic body. $\endgroup$
    – r13
    Aug 13 at 18:17

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.