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I am not sure how to draw a certain force in a FBD (Free Body Diagram) of a garage door. The Garage door is indicated by B-C (2m height) in the picture below. If this door is closing, how should the Force be drawn in hinge point 'B'?

enter image description here

Thanks

More specifically, what's the direction of the force in hinge point B? Should it be from point B to point D?

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  • $\begingroup$ this is a Q&A site ... not a chat forum ... please edit all information into your question and delete the comment $\endgroup$
    – jsotola
    Jul 30 at 19:07
  • $\begingroup$ Also, this looks like a homework question. Please edit your post to show what you tried so far. $\endgroup$
    – NMech
    Jul 30 at 19:13
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At any instant of closing the door, the force diagram is as shown below.

enter image description here

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  • $\begingroup$ Thanks! So there are 3 forces working on the door? The force you've drawn from point B pointed left downward, its weight and a normal force (vertically pointed above at C). Can you confirm that? $\endgroup$ Jul 31 at 17:50
  • $\begingroup$ You are correct, There are two force components at B, one vertical reaction at C. I made a mistake on my additional sketch, as C is a roller, there is no horizontal reaction. Sorry about that. (I've deleted the sketch) $\endgroup$
    – r13
    Jul 31 at 19:26

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