For the problem below, I tried solving it, but I don't know where I should get the value of normal acceleration, guess I was lost.enter image description here

enter image description here And here's what I solved so far enter image description here


1 Answer 1


You are almost there.

In order to calculate the tangential and the normal acceleration you need to take them as vectors.

enter image description here

The angles are

  • $\theta= \arctan(16/12)=-53.13 deg$ for velocity
  • $\phi= \arctan(16/12)=-26.51 deg$ for accelaration

Therefore the vectors for acceleration and velocity would be

enter image description here

And then you can find the component of tangential and normal acceleration as:

  • tangential: $a_t =a \cos(\theta-\phi)$
  • normal: $a_n =a \sin(\theta-\phi) = 5\frac{m}{s^2}$

Then you can just substitute:

$$R = \frac{v^2}{a_n}= \frac{20^2}{5}= \frac{400}{5}= 80 in$$

  • $\begingroup$ Help appreciated, arigatou $\endgroup$
    – keplerxx
    Commented May 13, 2021 at 13:29
  • $\begingroup$ Itsu demo dohzo $\endgroup$
    – NMech
    Commented May 13, 2021 at 13:55

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