I know when I have a source-sink pair with equal strength in a uniform flow, I get the rankine oval.

Lets say that my source is know +1.25*Q and my sink is -Q, would I still get some sort of "oval body"?

I think I'd still get flow over a closed body, correct me if I'm wrong.

  • $\begingroup$ If you have a Rankine oval, then there is another primitive field - A uniform velocity vector field lined up with your source sink pair. Decompose your source into two parts - Q and 0.25Q. You now have three primitive fields - the uniform field, the dipole field of strength Q, and a source of strength 0.25 Q. The total velocity field is the sum of these three fields. Each has a closed form formula over an infinite fluid domain. Bounded domains take a bit more work. $\endgroup$
    – Phil Sweet
    Apr 22 at 19:51

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