I am building a firewood storage cabinet which should support around
100-150 kg of firewood.
The cabinet is made out of wooden boards (
20 mm thick for all sides). The length is
550 mm and depth is
400 mm. The wooden logs are
300 mm in length.
150 kg for a wooded shelf of
20 mm in thickness is too much (I want to use 20 mm wood for all sides) and I want to make sure it will not bent. My idea is to reinforce the shelf with hollow steel rods under it. Round rods, because those can be easily drilled into the walls of the cabinet. I know square rods are stronger, but square holes are tricky to make.
The problem is that if the rod is thicker than
D=10 mm and the distance from the front is is more than
x=50 mm, the rod will be visible under the shelf from a distance (the shelf start at
340 mm from the ground). So I would like to keep the first rod around
x=100 mm from the front and use rods of
D=10 mm for the aesthetics of it.
I am not sure though if a rod of
D=10mm / d=2mm is strong enough for this. Or how many rods will be enough (
My question is, what size steel round ronds (
d) can I use and how many of them (
n) will be enough? Another option would be to only use the thinner rod front rod and thicker rods after. But I am also very curious how this can be calculated.
Below is the schematics with sizes and some variables which I used:
rod length = 550 mm total wood weight = 150 kg D = round rod diameter d = rod wall thickness n = number of rods needed to support the weight