To see why this graph can only have a hyperbolic shape, it can help to take a look at the energy balance of the laser cutting process with absorbed laser power $P_A$.
$$P_A = \underbrace{vtw}_{V_M}\cdot \rho \cdot \underbrace{(c_p \Delta T_P + h_M + \xi h_E)}_{\text{process energy}}+\underbrace{P_L}_{\text{losses}}$$
The term labelled "process energy" doesn't bother us further here, it describes the energy we need to put in to bring the material from environment temperature to process temperature and is constant for a given material. Same with the power losses $P_L$, maybe a little unintuitive, but experiments showed that they depend mainly on the thermal conductivity of the material, so we approximate them as constant as well. The material's density $\rho$ is of course also constant.
What remains? $V_M$, the molten volume per time, which consists of cutting velocity $v$, the sheet thickness $t$ and the width of our cut $w$. The width $w$ depends on the laser beam diameter, so we also consider $w$ constant.
In the end, only $v$ and $t$ are left. We consider everything in the energy balance except those two constant, so let's claim:
$$ v \cdot t = const.$$
A product being constant? That is just the equation of a hyperbola with the axes as asymptotes.