This question relates to a previous question (How to calculate the required torque in a static equilibrium system) where I have enquired about the start-up torque required to rotate a system. However, the parameters have changed slightly since then, and as a result I am not entirely sure if the system is still considered to be in "static equilibrium" - somehow I believe it still is, and I am speculating that the only factor that has changed is gravity, considering the additional weight added.
However, I do not know what other forces are now at play in the new system.
Question: What is the required start-up torque to rotate the system with the parameters provided below ?
This is what I have:
2x bars perpendicular to each other, intersecting each other at their centres. Something like this:
10kg (F3) | | | | 10kg (F1) ----------+---------- 10kg (F2) | | | | 10kg (F4) Bar weight : 0.5kg (500g) Axle weight : 0.5kg (500g) Max RPM : 3 RPM F1, F2, F3, F4 : 10kg each Time to Max RPM : 10sec *** Ignore Friction and Drag. The motor torque specification is given in kg.cm.
A motor (whose start-up torque requirements I need) is attached to an axle. The motor is required to turn the axle at a constant speed of about 3RPM. What is the required start-up torque to reach 3RPM after 10 sec ?
(I am hoping to hear from Kamran again)