0
$\begingroup$

So I am getting into engineering and was curious what it means when a sine wave isn't even in a sense, at 0, from my understanding, the waveform has peak to peak amplitude of 4, while having a positive peak of 3 and negative peak of 1, does it mean anything in specific when it isn't even at a positive peak of 2 and negative peak of 2?

enter image description here

$\endgroup$
2
$\begingroup$

It means that there is a positive offset of one. So your signal is

$$ x(t) = 1 + 2 \cdot \sin(\omega t)$$

where:

  • 1 is the offset
  • 2 is the amplitude of your signal (not 4).
$\endgroup$
1
  • $\begingroup$ Ahh that makes sense, thanks for the clarification $\endgroup$
    – Jack burns
    Jan 17 at 18:10

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.