Keep in mind that the failure doesn't have to follow a normal distribution. Weibull distribution is a much better fit for real life situations. And to be more specific, a weibull with a shape like the following. Near one end is very similar to a normal distribution but it is very skewed.
So regarding your data, the 22.1[kN] and the 20.7 [kN] seem like outliers based on the following kernel density plot.
However, unless you can identify valid reasons why they should be discarded, I suggest leaving them in the sample. The points could carry significant information. For example, it might give indication of the skewness of the distribution, or it might help you identify that its a multimodal distribution.
Regarding your question what is the best way to present the breaking force I would either go for:
a) plain simple average and standard deviation or
b) (preferably) give the value that 90% of the specimens are survived.
In this case, I would sort the data based on ascending order and take the average of the two lowest observations:
$$\frac{20.98+ 20.7}{2}= 20.84 [kN]$$
For 20.84 kN only one 1 in 10 specimens failed.
There are other fancy ways of doing it, but depending on who you are reporting to, it will most likely end up being "Lies, God damn lies and Statistics".