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Is it possible to constraint a line on another line by way of a perpendicular constraint? This also includes center points on other objects.

What I am trying to accomplish is to move a rectangular array to a set distance from another object (all in sketch) at the center points. So basically, I need to move this array to a set location from the corner or another object (inside the object which is a rectangle)

I have been trying to get this to work in different ways for the past 3 hours with no luck or even trying to find additional help on the Autocad inventor forums.

Please keep in mind, I am VERY new to Inventor (started with Fusion and, YUP, there are a ton of differences). Are there even guidelines? I will not be able to use the grid as my measurements are not a whole number and precision is 3 places.

Hopefully, I have explained what I am trying to accomplish, If you need any further information to assist me in answering this question, please do not hesitate to ask. :)

Attached is a sample of what I am dealing with. the column of objects HAS to be x, y from the top and right sides of the outer rectangle. The additional lines outside of the rectangle in the upper right are directional lines for creating arrays only.

Sample

Thanks in advance.

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  • $\begingroup$ Yes this is 100% possible. Please can you provide screenshots to clarify your exact situation? $\endgroup$
    – Jonathan R Swift
    Commented Jan 4, 2021 at 11:48
  • $\begingroup$ (I don't have inventor installed any more so can't provide screenshots of my own) $\endgroup$
    – Jonathan R Swift
    Commented Jan 4, 2021 at 11:49
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    $\begingroup$ just now updated $\endgroup$
    – John Schultz
    Commented Jan 4, 2021 at 13:18
  • $\begingroup$ So the problem is that the black lines are in a different sketch, so you can't directly dimension to them? If so then you need to use a tool called project geometry, which will will make a a copy of the black lines in in yellow, which you can then dimension to. $\endgroup$
    – Jonathan R Swift
    Commented Jan 4, 2021 at 20:18
  • $\begingroup$ You can also create a point in your sketch (to the right of the spine button), and define it's position using constraints to give you something more intuitive to to dimension against. For example by assigning it's to the midpoint of a line, or to be coincident to two different lines giving a virtual intersection $\endgroup$
    – Jonathan R Swift
    Commented Jan 4, 2021 at 20:21

1 Answer 1

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Ok, so I've re-installed Inventor...

It's only now become apparent to me that your slot is actually a rectangle with all four corners filleted?

If you instead create a 'slot' entity directly, then the relevant point will be automatically created for you, ready for dimensioning.

In any case, below I have shown both how to add the point I was describing before to allow you to dimension to the midpoint, and also I have shown how to make a slot entity instead, which is better practice

enter image description here

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  • $\begingroup$ OMG! You are awesome sir! Thank You. $\endgroup$
    – John Schultz
    Commented Mar 16, 2021 at 8:52
  • $\begingroup$ No problem! Took a while for you to notice my answer, it seems 😅 $\endgroup$
    – Jonathan R Swift
    Commented Mar 16, 2021 at 13:38
  • $\begingroup$ Sorry dude.... I've been having health issues for more than a year, so ... yeah. :( $\endgroup$
    – John Schultz
    Commented Mar 20, 2021 at 1:27

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