The figure shows a metallic structure composed of two beams $AB$ and $BC$ connected to each other by a pin in $B$, the structure being supported in A and C through fixed supports. In the AB beam, a constant distributed load $ w= 300 N /m$ and a torque counterclockwise $M_D = 600 Nm$ are applied. Disregard the proper weight of the structure
Determine the reactions on supports $A$ and $C$ and write the functions of the internal forces for the beam sections $AB$
I've done this free body diagramm
Then i got $R(Ax)=0$ and $R(Ay)=0 $and $R(Cy)=800N$, $R(Ay)=1000N$,$ F=-800N$
But in the solutions they said that $R(Ax)=-1920N $and that$ R(Cx)=1920 N$ How to i get to this results?
For the writing the internal forces for the beam i've calculated correctly for $0<x<3$ but for $3<x<6$ i am not getting the correct result (the correct result $V(x) = -300 x+ 1000$ ; $M(x) = -150 x^2 +1000 x -600$)
However i got
and i know that this is wrong because $d/dx M(x)$ is not igual to $V(x)$
Could someone help me?
Edit: i notice that i forget to draw a Force in X for B
UPDATE: i already understand why my body diagramm for 3<x<6 and why my expression for V(x) and M(x) are wrong (i forgot to draw the moment and i should't have drawn the 800 force and the (x-3) is also incorrect)