# Vector expression of bearing pressure

I have been trying to solve the problem below involving a concrete anchor block subject to two equal horizontal forces. Normally I would just apply the force as a moment acting about the centroid of the concrete block which would produce a linear bearing pressure distribution at the base. Adding the self weight of the block as a compressive bearing pressure and I would then have an idea of the complete bearing pressure distribution. Am I missing something? taking moments about the centroid with the forces turned into vectors via the position vector and using the cross product only gets me so far.

$$\Sigma M_y=0,\quad (1500+1500)5kNm=2(Q*7.5/2)_{total\ stress}*(15*1/3)_{lever\ arm}$$ $$Q=15kNm/37.5=400N$$ but this is for the 5 meters base width, therefore $$400/5=80N/m^2$$
The slope of this stress surface is $$80/7.5=10.66\text{ N}$$ per meter. With 0 stress at the middle of the 15m length.
So the total stress distribution is $$P_{total}=(P-80+10.7*x)Nm2$$