For a National Board Exam Review:
An air conditioning plant with a capacity of $400$ $kW$ of refrigeration has an evaporating and condensing temperature of $3$ $^oC$ and $37$ $^oC$ respectively. If it uses Refrigerant 12, what volumetric rate of flow under suction condition?
Answer is $0.172$ $m^3/s$
So I try:
$${ V = mv}$$
$${ COP = \frac{T_{min}}{T_{max} - T_{min}} = \frac{Q_A}{W} = \frac{h_1 - h_4}{h_2 - h_1}}$$
$${ COP = \frac{ (3 + 273) }{37 - 3} = \frac{400}{W} = \frac{400}{h_2 - h_1}}$$
$${ W = h_2 - h_1 = 49.24859678 kJ/kg }$$
I've viewed every formula in the book and many other books. I cannot find a way to find m, for mass. even so... it's also hard to find the specific volume of freon without a given temperature. How am I supposed to go about this?