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I tried to solve this block but I am not sure if the end result is any good, some feedback would be nice. enter image description here

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  • $\begingroup$ Do you want positive or negative feedback? Jokes aside, your working out looks correct. $\endgroup$ – fibonatic Aug 31 '20 at 22:21
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Your answer is incorrect. Problem lies in going from step 2 to 3. (1-G5) term can be taken in denominator of G4 only if they are in feedback loop. In this case, they are not in loop and as a result, your answer is wrong. The correct answer would be:
Y=X[(G5+(G1/(1-G1G3)(1-G5)))G2+G1G4/(1-G1*G3)]
Thank you

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