# Deflection of a cantilever beam composed of separate (not bonded) planks Uniform load

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It is the case of a simple cantilever beam having a uniform rectangular cross-section.

cantilever beam composed of separate planks - taken from The question in the original post was What happens if we split it along its longitudinal axis? @sudhir asked What would happen if the beam was loaded uniformly

$$\delta_{decoupled, concentrated} = 9 \delta_{coupled,concentrated}$$
If you change to a uniform load then with respect to the relative deflection of the coupled/decoupled would remain the same. i.e. $$\delta_{decoupled, uniform} = 9 \delta_{coupled, uniform}$$
Of course, the total deflection would be less because the formula for $$\delta$$ will change(see link ).
Assuming that the distributed load is $$w=\frac{P}{l}$$ (so that the total load is the same for comparison purposes:
$$\delta_{coupled, uniform} = \frac{w\cdot l^4}{4\cdot I_{coupled}}=\frac{P\cdot l^3}{4\cdot I_{coupled}} = \frac{3}{4} \delta_{coupled, concentrated}$$