Per the ME Pavement Design Guide MOP, Section 5.3.6, Eq 5-18b, how is p02 assumed if not entered in Pavement ME?

The MOP, equation 5-18b calls for p02, which the MOP describes as the "Percent passing the 0.02 mm sieve". I assume that this is the percent passing for the subgrade. We only input down to the p200 for our subgrades. For example, our clay entry is the following:

• 3/8” = 99.9
• No. 4 = 99.5
• No. 10 = 97.7
• No. 20 = 96.0
• No. 40 = 90.7
• No. 100 = 68.3
• No. 200 = 57.5

Therefore, how is Pavement ME calculating the p02 input for us of the site factor (SF)?

Note that if 0 is assumed, then the equation would have an error because LN(0) is undefined (ie. no value), so I assume that some value must be assumed.

• Welcome to Engineering! I'm not a pavement engineer, so don't know. However, I'd assume they adopt the "worst case". I assume a high SF is bad (since it's proportional to age), so it seems the worst case would be to assume that $p_{02} = p_{200}$.
– Wasabi
Jul 16, 2020 at 14:33
• @Justin Schenkel Which edition is the manual? I suspect, in front of each of the percent passing, there is a number missing, as you've noted, Ln(0) is undefined, I suggest to check the errata, or contact AASHTO for clarification.
– r13
Feb 22, 2021 at 20:28

The MOP, equation 5-18b calls for p02, which the MOP describes as the "Percent passing the 0.02 mm sieve". I assume that this is the percent passing for the subgrade.

The percent passing parameter in the equation IS taken from the subgrade layer inputs. However, there is a typo in the IRI equation in the MOP. The IRI model actually uses the percent passing of the #4 sieve and not the p02 sieve of the first subgrade layer in the pavement structure.

Initially, the IRI model used the p02 sieve in the original NCHRP 1-37A project but was adjusted in subsequent work and the documentation for the MOP wasn’t updated. I wasn’t able to find a specific reference documenting when this change was implemented into the software but has been included since at least 2015 and likely before that.

The corrected equations for the site factor are shown below.

$$IRI=InitialIRI + C1\times TotalRutting + C2\times TotalCracking + C3\times TotalTransverse + C4\times SiteFactor$$

$$SiteFactor=(Frost + Swell)\times Age ^{1.5}$$ $$Frost=Ln[(Precipitation+1)\times(FreezingIndex+1)\times P_4 ]$$ $$Swell=Ln[(Precipitation+1)\times(PlasticityIndex+1)\times P_{200} ]$$ SiteFactor = Site factor
Age = Pavement age (years)
FreezingIndex = Mean annual Freezing index, °F-days.
PlasticityIndex = Plasticity Index
Precipitation=Mean annual precipitation(in.)
P4 = Percent subgrade material passing No. 4 sieve
P200 = Percent subgrade material passing No. 200 sieve