# How many kWh this turbine would generate?

My grandfather and I are running some experiments down the river, however we don't have expertise in engineering so I bring up this question to the community and hope someone could help.

How many kWh a turbine with the following features would generate?

These images are just a simple prototype which does not apply some of the following features:

Shape: Reel.

Length: 1.50m.

Diameter: 1.20m. (Including its palettes and axis which has the thickness of 20cm.)

10 Longitudinal/helical palettes with length of 1.50m., thickness of 2cm. and height of 50cm.

Total weight: 50kg. (Palettes and axis included for torque boost.)

Flow rate (amount flowing through the device): 3m³/s

River conditions:

Flow rate: 209.000 m³/s

Speed: 2 meters per second.

Depth: 40m.

It would be installed 2 meters beneath the river surface, placed horizontally.

• Power developed won’t be from the flow of the whole river but the amount flowing through the device. Check out water wheel calculations... Mar 23 '20 at 4:48
• this question was already answered on the physics stack exchange. Mar 23 '20 at 17:55
• @nielsnielsen According to your answer on the physics stack exchange I did update my question with the Flow rate condition as you can see, by the way my question on the physics stack exchange has been closed because they suggested me to recreate a new one on the engineering stack exchange, so I did it. Mar 23 '20 at 23:02
• No, @Rafa. Energy = power x time. The unit of power (for this exercise) is the kW and the unit of energy is the kWh. The energy produced per hour is P x t = kW x h = kWh. Understanding this is important for your project. Mar 28 '20 at 0:01
• It seems to me that you can eliminate all the drag of the convex sections moving against the flow by mounting the device on the surface with the axle horizontal and at surface level. That way the returning "pallettes" are only resisted by air. Mar 28 '20 at 0:06