Context: I have a lead screw rod, nut and a pulley aligned vertically. The nut is attached on top of the pulley so their respective bores are aligned and the rod is arranged so that it is threaded through the nut but its diameter is smaller than the pulley bore so no contact is made between rod and pulley.
When the pulley spines the nut turns, because the pulley and nut are in a fixed position the rod moves up and down via the spinning nut and through the pulley bore. Essentially a linear actuator.
Problem: My problem is how to support the rod from lateral load. Please could you comment on the validity of my proposed solutions and propose your own if you have something more effective
Potential Solutions: A: The most obvious to me would be to have a linear guide rail with a linear bearing in parallel and a secondary nut on the threaded rod that is not fixed like the first nut so that as the rod moves up and down the secondary nut provides support via the guide rail. The issue with this is it predetermines the height of the mechanism as it will be has high as the linear guide rail, I would like the height to be as small as possible.
B: Put a linear bearing through the rod and fix it's position to the wall of the actuator so that as the rod moves up and down it moves through the linear bearing which provides support via the wall. The issue with this is I think linear bearings are designed for smooth rods and the gaps in the threaded rod could allow the ball bearings to flick out under load, is this a correct assumption ?
C: Have 3-4 roller bearings arranged around the outside of the rod, so that the rod moves between the bearings. The issue is I don't know if there is enough contact area to be effective.
I appreciate what I am essentially looking for is a spline shaft, but that is not something I have access to so I am trying to mimic the linear aspect using a regular lead screw
All help appreciated.