0
$\begingroup$

I'm a bit confused with the wording of the question. What does it mean by expressing the bending moment and the deflected shape of BC as a function of z? Thank you![enter image description here]1

enter image description here

$\endgroup$

3 Answers 3

2
$\begingroup$

In this question, the axes x and y are in the plane of the cross-section of the beam and z is along the length of the beam pointing horizontally to the right.

The reaction forces are,

$$ \Sigma M_C=0 \quad 20kN*4*2+ 30kN*6-B_V*4=0 \\ B_v = 340kN/4 =85kN \\ C_v= 80+30-85=25kN $$

The moment on the cantilever part is $$ M= 30kN*( z+2) \ assuming\ z_B =0 $$ And I let you do the deflection,by either double integration or area moment.

$\endgroup$
0
$\begingroup$

You need to find the right expression that explains the bending moment along the z dimension.

Something like for $z=2meters$ (your limit is $-2m<=z<=4m$) the bending will be max. And for $z=4meters$ the bending will be 0mm.

I'll not put the equation here because this looks like a homework question so you can find with your own material.

$\endgroup$
0
$\begingroup$

1.) Find all the reaction forces first, then draw a SFD diagram.

2.) Express the shear force using z as variable, you will get your f(z).

3.) Then calculate the bending moment, then draw a BMD diagram.

3.) Integrate the shear force equation from 2.) into a bending moment equation f'(z) with a constant C at the back.

4.) Identify the constant C in the bending moment equation with the maximum moment.

5.) Integrate the bending moment equation from 4.) into a deflection equation f''(z) with a constant C at the back.

6.) Identify the constant C in the deflection equation, substitute back into f''(z).

Then you are done, a deflection equation f''(z) in terms of z.

$\endgroup$

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge that you have read and understand our privacy policy and code of conduct.

Not the answer you're looking for? Browse other questions tagged or ask your own question.