# Storage losses of a heat storage tank

Suppose I have a heat generator with a connected heat storage tank. If the heat generator remains the same and the heat storage tank is dimensioned larger, the running time of the heat generator increases due to the higher storage losses. Why is this so?

Normally, the surface with exponent 2 and the volume increases with exponent 3 - should the heat storage tank not have fewer losses?

• More material to heat.. – Solar Mike Nov 8 '19 at 8:36

Heat loss due to conductivity of the walls of your container assuming the ambient outside temperature, $$\frac{\Delta Q}{\Delta t*A}=-k \frac{\Delta T}{\Delta x} =C_{constant}$$
• Thank you very much. Would you mind giving me an exemplary calculation for two cylindrical heat storages - one with A = 6$m^2$ (~1000 liters) and the other one with A = 11$m^2$ (~2000 liters); both start at 90 °C and have an ambient temperature of 20 °C. – MerklT Nov 8 '19 at 23:11